How do i solve these?
1 answer:
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Given:
Distance between two buildings = feet apart.
Distance between highway and one building = feet.
Distance between highway and second building = feet.
To find:
The standard form of the polynomial representing the width of the highway between the two building.
Solution:
We know that,
Width of the highway = Distance between two buildings - Distance of both buildings from highway.
Using the above formula, we get the polynomial for width (W) of the highway.
Combining like terms, we get
Therefore, the width point highway is .
1.
In any trapezoid, the length of the midsegment is
substituting the known values:
2.
Notice that since D and have the same y-coordinate, then DE is horizontal, and since F and D have the same x-coordinate, FD is vertical.
Thus FD and DE are perpendicular, so the triangle FED is a right triangle.
The median drawn from the right angle, is equal to half the hypotenuse.
That is, |DO|=1/2 |FE|, thus |OE|=|OF|=|OD|, are all radii of the circle centered at O.
O is the midpoint of EF, and is found by the Midpoint formula:
Answer:
1. 14
2. (4, 3)
In any trapezoid, the length of the midsegment is
substituting the known values:
2.
Notice that since D and have the same y-coordinate, then DE is horizontal, and since F and D have the same x-coordinate, FD is vertical.
Thus FD and DE are perpendicular, so the triangle FED is a right triangle.
The median drawn from the right angle, is equal to half the hypotenuse.
That is, |DO|=1/2 |FE|, thus |OE|=|OF|=|OD|, are all radii of the circle centered at O.
O is the midpoint of EF, and is found by the Midpoint formula:
Answer:
1. 14
2. (4, 3)