That would be the commutative property
The area of the trapezoid is the product of the height and the average of the two bases:
<span>30 (25 + 33)/2 = 30 (58)/2 = 30 (29) = 870 square yd. </span>
<span>But we want to exclude the area of the fountain. </span>
<span>Since it's circular its area is π times the square of its radius, or 16π square yd. </span>
<span>So the area of the park, excluding the fountain, is </span>
<span>870 - 16π square yd, </span>
<span>or about 820 square yd.</span>
Answer:
There are 70 sheep in the farm.
Step-by-step explanation:
Consider the provided information.
Let c represents the cows, s represents the sheep and p represents the pigs.
The number of cows and the number of sheep are in the ratio 6:5.


The number of sheep and the number of pigs are in the ratio 2:1.


The total number is 189.

Substitute the value of c and p in above.




Hence, there are 70 sheep in the farm.
Answer:
8\sqrt{2}\ units.
Step-by-step explanation:
Use the trignometric property.
sin\theta = \frac{Perpendicular}{Hypotenuse}
Perpendicular = 8
Hypotenuse = h
\theta = 45^{\circ}
sin\ 45^{\circ} = \frac{1}{\sqrt{2}}
\frac{1}{\sqrt{2}} = \frac{8}{h}
h = 8\sqrt{2}\ units
Hope I helped you! x
Answer:
1. x = 39.67
2. x = 15
3. x = 49.29
4. x = -12.8
5. x = 96
6. x = 42
7. x = 36
8. x = 0
9. x = 78
Step-by-step explanation:
Just remember to always isolate the unknown. Here are the solutions to your problem. I will explain each step for the first for you to give you an idea how the others were worked out.
1.
Add 2 to both sides to get rid of -2 on the left side.

Multiply both sides by 7 to get rid of 7 on the left side.

Divide both sides by 3 to get rid of 3 on the left side.

You could also transpose everything by the x to the other side of the equation. Just remember that whatever OPERATION used on the original side, must be opposite on the other side. I'll use the second problem to show this.

Transpose 1 on the left to the right. It is addition on the left, then it would be subtraction on the other side.

Transpose 5 from the left side to the right. It is division on the left, then it would be multiplication on the right.

Transpose 2 from the left side to the right. It is multiplication on the left, then it would be division on the right.

Let's move on with the rest now.
3.

4.

5.

6.

7.

8.

9.
