All categories

3 years ago

What is 99999999+-4?

Mathematics

2 answers:

iVinArrow [24]3 years ago

8 0

99,999,999 + (-4) is basically 99,999,999 - 4

99,999,999 - 4 = 99,999,995

juin [17]3 years ago

4 0

99999999+-4 is actually 99999999-4 so remember that a positive plus a negative is actually subtracting a positive so 99999999+(-4) is <span>99999995.</span>

You might be interested in

Convert the angle \theta=260^\circθ=260

mel-nik [20]

Question:

Convert the angle θ=260° to radians.

Express your answer exactly.

θ = ___ radians

Answer:

260° = 13π/9 or 4.54 rad

Step-by-step explanation:

Given

θ=260°

Required

Convert from degree to radians

To convert an angle in degrees to radians, we simply follow the steps below.

1° = 1 * π/180 rad

Replace the 1° with x

So,

x° = x * π/180 rad.

Now, we assume that x = 260

This means that we substitute 260 for x. This gives

260° = 260 * π/180

260° = 260π/180

Divide numerator and denominator by 20

260° = 13π/9

We can leave the answer in this form or solve further.

Take π as 22/7. This gives

260° = 13/9 * 22/7

260° = 286/63

260° = 4.5396825397

260° = 4.54 rad (Approximated)

3 0

3 years ago

Which has the greater slope B is not the answer ...

olga nikolaevna [1]

B is the answer.

The slope i got for the table is -1 because i divided -2 by 2.

The slope i got for the graph was 0 because 0/7 is 0.

-1 < 0

6 0

3 years ago

What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?

Natasha2012 [34]

Answer:

$x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}$ are zeroes of given quadratic equation.

Step-by-step explanation:

We have been a quadratic equation:

$2x^2-10x-3$

We need to find the zeroes of quadratic equation

We have a formula to find zeroes of a quadratic equation:

$x=\frac{b^2\pm\sqrt{D}}{2a}\text{where}D=\sqrt{b^2-4ac}$

General form of quadratic equation is $ax^2+bx+c$

On comparing general equation with b given equation we get

a=2,b=-10,c=-3

On substituting the values in formula we get

$D=\sqrt{(-10)^2-4(2)(-3)}$

$\Rightarrow D=\sqrt{100+24}=\sqrt{124}$

Now substituting D in $x=\frac{b^2\pm\sqrt{D}}{2a}$ we get

$x=\frac{(-10)^2\pm\sqrt{124}}{2\cdot 2}$

$x=\frac{100\pm\sqrt{124}}{4}$

$x=\frac{100\pm2\sqrt{31}}{4}$

$x=\frac{50\pm\sqrt{31}}{2}$

Therefore, $x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}$

5 0

3 years ago

Read 2 more answers

4f2 + 3h - g+f

Bas_tet [7]

Answer:

can't be simplified or you can add you get the answer

4 0

2 years ago

Geometry; building blocks

notka56 [123]

Answer:

128 degrees because it is a suplimentary angle which adds up to be 180...so you subtract 180-52 and you get 128

7 0

2 years ago