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geniusboy [140]
3 years ago
9

Can someone please take the time out of they’re day and help me and with this question

Mathematics
1 answer:
Bumek [7]3 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

(a)

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (0, 100) and (x₂, y₂ ) = (2, 200) ← 2 points on the line

m = \frac{200-100}{2-0} = \frac{100}{2} = 50

The line crosses the y- axis at (0, 100 ) ⇒ c = 100

y = 50x + 100 ← equation of line

where y is monthly savings and x the time in months

(b)

Slope is the monthly deposit , that is $50 per month

The y- intercept indicates the original amount in her account , that is $100

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3 years ago
WHY IS THIS GETTING DELETED?? I NEED HELP
aliina [53]

If this exact question is repeatedly deleted, it's probably because of the ambiguity of the given equation. I see two likely interpretations, for instance:

\dfrac{(5\times5)^k}{5^{-8}} = 5^3

or

\dfrac{5\times 5^k}{5^{-8}} = 5^3

If the first one is what you intended, then

\dfrac{(5\times5)^k}{5^{-8}} = \dfrac{(5^2)^k}{5^{-8}} = \dfrac{5^{2k}}{5^{-8}} = 5^{2k-(-8)} = 5^{2k+8} = 5^3

and it follows that

2<em>k</em> + 8 = 3   ==>   2<em>k</em> = -5   ==>   <em>k</em> = -5/2

If you meant the second one, then

\dfrac{5\times 5^k}{5^{-8}} = \dfrac{5^1\times5^k}{5^{-8}} = \dfrac{5^{k+1}}{5^{-8}} = 5^{k+1-(-8)} = 5^{k+9} = 5^3

which would give

<em>k</em> + 9 = 3   ==>   <em>k</em> = -6

And for all I know, you might have meant some other alternative... When you can, you should include a picture of your problem.

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Below is the data on the percentage of 25- to 34-year-olds in each of the 50 states and the District of Columbia, listed in alph
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Answer:

Step-by-step explanation:

Given the following data:

31.5 32.9 33.0 28.6 37.2 43.3 45.9 37.2 68.8 36.2 35.5 31.5 32.9 33.0 28.6 37.2 43.3 45.9 37.2 68.8 36.2 35.5 40.5 37.2 45.3 36.1 45.5 42.3 33.3 30.3 37.2 45.5 54.3 37.2 49.8 32.1 39.3 40.3 44.2 28.4 46.0 47.2 32.8 32.2 38.5 44.5 44.6 40.9 29.5 41.3 35.4

Value ___frequency____relative frequency %

28.4_______1 __________1. 96

28.6_______2__________3.92

29.5_______1___________1.96

30.3_______1___________1.96

31.5_______2___________3.92

32.1_______1____________1.96

32.2_______1___________1.96

32.8_______1___________1.96

32.9_______2___________3.92

33________2___________3.92

33.3_______1___________1.96

35.4_______1___________1.96

35.5_______2___________3.92

36.1________1___________1.96

36.2_______2___________3.92

37.2_______7___________13.73

38.5_______1____________1.96

39.3_______1____________1.96

40.3_______1____________1.96

40.5_______1____________ 1.96

40.9_______1____________1.96

41.3_______1 ____________1.96

42.3______1_____________1.96

43.3______2____________ 3.92

44.2______1 _____________1.96

44.5______1 _____________1.96

44.6_____ 1 ______________1.96

45.3_____1 _______1.96

45.5_____2 ______3.92

45.9_____2 ______3.92

46______1 _______1.96

47.2_____1 _______1.96

49.8_____1 _______1.96

54.3____1________1.96

68.8____2________3.92

Lower outlier = Q1 - (1.5 × IQR)

Upper outlier = Q3 + (1.5 × IQR)

IQR = Interquartile range ;

Q1 = 1/4(n+1)th term

Q3 = 3/4(n+1)th term

IQR = Q3 - Q1

n = number of observations = 51

Q1 = (51 + 1)/4= 52/4 = 13 th term = 33

Q3 = 3(51 + 1) /4 = 156/4 = 39th term = 44.5

IQR = 44.5 - 33 = 11.5

LOWER OUTLIER = 33 - (1.5*11.5) = 33 - 17.25 = entries < 15.75

UPPER OUTLIER = 44.5 + (1.5*11.5) = 44.5 + 17.25 = 61.75

Entries > 61.75

7 0
3 years ago
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