20x^2-19x+3 divided by 5x-1
2 answers:
20x^2 - 19x + 3 / 5x - 1
400x - 19x + 3 / 5x - 1
381x + 3 / 5x - 1
381x - 5x + 3 / 5x - 5x - 1
376x + 3 / -1
376x + -3
(20x^2-19x+3)/5x-1
(400x-19x+3)/5x-1
(381x+3)/5x-1
381x/5x-1 + 3/5x-1
(381/5-381) + (3/5x -3)
(76.2-381) + (3/5x -3)
304.8 + 3/5x-3
101.8 +3/5x
That's what I got. I'm not too sure if it helps though.
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Answer:
not sure but this should be it
Any 2 adjacent angles whose outer angles form a straight line are considered supplementary
L=26
N=10
So it's 26*26*10*10*10*10=6760000
The nearst rounding to the tens is 230
