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3 years ago

20x^2-19x+3 divided by 5x-1

Mathematics

2 answers:

Ratling [72]3 years ago

7 0

20x^2 - 19x + 3 / 5x - 1
400x - 19x + 3 / 5x - 1
381x + 3 / 5x - 1
381x - 5x + 3 / 5x - 5x - 1
376x + 3 / -1
376x + -3

BabaBlast [244]3 years ago

3 0

(20x^2-19x+3)/5x-1
(400x-19x+3)/5x-1
(381x+3)/5x-1
381x/5x-1 + 3/5x-1
(381/5-381) + (3/5x -3)
(76.2-381) + (3/5x -3)
304.8 + 3/5x-3
101.8 +3/5x

That's what I got. I'm not too sure if it helps though.

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Step-by-step explanation:

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2 years ago

Hey fellas, giving brainliest and a lot of points to who gets this correct

Ainat [17]

Answer:

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Step-by-step explanation:

total boxes = Jills boxes + Mikes boxes

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3 years ago

The answer to this problem?

LenaWriter [7]

The simplified expression of $\sqrt{\frac{162x^9}{2x^{27}}}$ is $\frac{9}{x^9}$

<h3>How to simplify the expression?</h3>

The expression is given as:

$\sqrt{\frac{162x^9}{2x^{27}}}$

Divide 162 and 2 by 2

$\sqrt{\frac{81x^9}{x^{27}}}$

Take the square root of 81

$9\sqrt{\frac{x^9}{x^{27}}}$

Apply the quotient rule of indices

$9\sqrt{\frac{1}{x^{27-9}}}$

Evaluate the difference

$9\sqrt{\frac{1}{x^{18}}}$

Take the square root of x^18

$\frac{9}{x^9}$

Hence, the simplified expression of $\sqrt{\frac{162x^9}{2x^{27}}}$ is $\frac{9}{x^9}$

Read more about expressions at:

brainly.com/question/723406

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alukav5142 [94]

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Step-by-step explanation:

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