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Marysya12 [62]
3 years ago
10

Starting with x = 0.773, express x as a fraction in simplest form.

Mathematics
2 answers:
Stella [2.4K]3 years ago
8 0
Steps to convert decimal into fraction

Write 0.773 as
0.773
/1

Multiply both numerator and denominator by 10 for every number after the decimal point

0.773 × 1000

1 × 1000
=
773/
1000

Reducing the fraction gives
773/
1000
jenyasd209 [6]3 years ago
5 0

Answer:

773/1000

Step-by-step explanation:

x = 0.773 \\  \\ x =  \frac{773}{1000}  \\

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A sphere has a diameter of 22 units what is the radius and volume
lilavasa [31]

Answer:


Step-by-step explanation:

11

7 0
3 years ago
If the ratio of black jeans to bluejeans is 6 to 18 with a total of 240 jeans how many of them are blue
Leya [2.2K]
The ratio is 6:18 and you are trying to find out what are blue. You divide 240 by 6 and get 40. You then multiply 40 x 18 and get 720.
5 0
3 years ago
Which of the following expressions are equivalent to \left(9\dfrac{7}{8} + 2\dfrac{4}{5}\right)-\dfrac{1}{2}(9 87​ +2 54​ )− 21​
lora16 [44]

Answer:

12\dfrac{7}{40}

Step-by-step explanation:

The given expression is

\left(9\dfrac{7}{8} + 2\dfrac{4}{5}\right)-\dfrac{1}{2}

We need to find the simplified form of the given expression.

It can be rewritten as

\left(9+\dfrac{7}{8} + 2+\dfrac{4}{5}\right)-\dfrac{1}{2}

Combine integers and fractions separately.

(9+2)+(\dfrac{7}{8}+\dfrac{4}{5}-\dfrac{1}{2})

Taking LCM we get

11+\dfrac{35+32-20}{40}

11+\dfrac{47}{40}

In can be written as

11+\dfrac{40+7}{40}

11+1+\dfrac{7}{40}

12+\dfrac{7}{40}

12\dfrac{7}{40}

Therefore, the expression 12\dfrac{7}{40} is equivalent to the given expression.

5 0
3 years ago
What is the mode and mean for class A and the range and medium for class B????
melamori03 [73]
Hello!

First you have to list the data in both classes

Class A
41, 42, 45, 46, 47, 48, 52, 53, 54, 59, 61, 61, 64, 68, 71, 82, 85, 90

Class B
41, 42, 59, 62, 64, 69, 71, 75, 77, 78, 78, 80, 83, 84, 84, 86, 86, 87, 92, 92, 95
------------------------------------------------------------------------------------------------------
First we are going to find the mode and mean of class A

The mode is the number that appears the most

The number that appears the most is 61

The mode is 61

To find the mean you add all the numbers together and divide the sum by the amount of numbers added

41 + 42 + 45 + 46 + 47 + 48 + 52 + 53 + 54 + 59 + 61 + 61 + 64 + 68 + 71 + 82 + 85 + 90 = 1069

Divide this by the amount of numbers added

1069 / 18 = 59.3888...

The mean is 59.3888

The mode is 61 and the mean is 59.39 for class A
------------------------------------------------------------------------------------------------------
We are going to find the range and median for class B

To find the range you subtract the smallest number from the largest on

The smallest number is 41
The largest number is 95

Subtract these

95 - 41 = 54

The range is 54

To find the median you list the numbers from least to greatest and look for the number in the middle

41, 42, 59, 62, 64, 69, 71, 75, 77, 78, 78, 80, 83, 84, 84, 86, 86, 87, 92, 92, 95

The number in the middle is 78

The range is 54 and the median is 78
------------------------------------------------------------------------------------------------------
Hope this helps!
6 0
4 years ago
Mary leaves her house to take a walk. The graph shows the distance, d, in feet from her house that Mary is at any given time, t,
Vitek1552 [10]
You haven't provided the graph, therefore, I cannot provide you with a specific solution for this question.
However, I will tell you how to solve it and you can apply on the graph you have.

Now, we are given that:
x-axis represents the distance in ft
y-axis represents the time in minutes

To get the time that she has walked when she reaches the farthest point from her house, all you have to do is:
1- go to the greatest point on the x-axis. This point would be representing the farthest distance.
2- get the value of the y corresponding to the x-point you got in step one. This would be the time walked when she reaches the farthest point which is the value you are looking for.

Hope this helps :)
5 0
4 years ago
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