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Verizon [17]
3 years ago
11

What type of number is 0.888...?

Mathematics
2 answers:
True [87]3 years ago
4 0
The number 0.888 is a decimal.
denis23 [38]3 years ago
4 0

I am pretty sure it is a rational, non terminating repeating decimal. If the eight goes on forever.

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Show work<br> Find the volume of the pyramid
Burka [1]
<u></u><em>Hello there, and thank you for posting your question here on brainly.

______________________________________________________________
Answer: 128
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<em>Why?
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To find the volume of a cylinder, we have to use the formula lwh/3. The length is 8, width is 4, and height is 12. So we have to multiply all of those together, then divide by 3. (8 * 4 = 32) -> (32 * 12 = 384) -> (384/3 = 128) The volume is 128.

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3 0
4 years ago
The order pairs (1, 2), (2, 5), (3, 10), (4, 17), and (5, 26) represent a function. what is a rule that could represent this fun
LenaWriter [7]
The X which is the first number in each () in called the input
There is only one input for every number
Meaning all the first numbers mystery br DIFFERENT
6 0
3 years ago
{4x-2y+5z=6 <br> {3x+3y+8z=4 <br> {x-5y-3z=5
lesya692 [45]

There are three possible outcomes that you may encounter when working with these system of equations:


  •    one solution
  •    no solution
  •    infinite solutions

We are going to try and find values of x, y, and z that will satisfy all three equations at the same time. The following are the equations:

  1. 4x-2y+5z = 6
  2. 3x+3y+8z = 4
  3. x-5y-3z = 5

We are going to use elimination(or addition) method

Step 1: Choose to eliminate any one of the variables from any pair of equations.

In this case it looks like if we multiply the third equation by 4 and  subtracting it from equation 1, it will be fairly simple to eliminate the x term from the first and third equation.

So multiplying Left Hand Side(L.H.S) and Right Hand Side(R.H.S) of 3rd equation with 4 gives us a new equation 4.:

4. 4x-20y-12z = 20      

Subtracting eq. 4 from Eq. 1:

(L.HS) : 4x-2y+5z-(4x-20y-12z) = 18y+17z

(R.H.S) : 20 - 6 = 14

5. 18y+17z=14

Step 2:  Eliminate the SAME variable chosen in step 2 from any other pair of equations, creating a system of two equations and 2 unknowns.

Similarly if we multiply 3rd equation with 3 and then subtract it from eq. 2 we get:

(L.HS) : 3x+3y+8z-(3x-15y-9z) = 18y+17z

(R.H.S) : 4 - 15 = -11

6. 18y+17z = -11

Step 3:  Solve the remaining system of equations 6 and 5 found in step 2 and 1.

Now if we try to solve equations 5 and 6 for the variables y and z. Subtracting eq 6 from eq. 5 we get:

(L.HS) : 18y+17z-(18y+17z) = 0

(R.HS) : 14-(-11) = 25

0 = 25

which is false, hence no solution exists



3 0
3 years ago
What is the solution to the inequality below. x(absolute value) &lt;5
jok3333 [9.3K]

Answer:

-5 < x < 5

Step-by-step explanation:

|x| < 5

This can be split into two cases: x < 5 and -x < 5 because |x| could be either x or -x depending on whether x is positive, negative, or 0. Solving the second one we get x > -5 so the answer is -5 < x < 5.

8 0
3 years ago
Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays
katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is 14.28days^{-1}

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

m(t)=m_o(1/2)^{t/h}

where,

m(t) =  amount of sample after time 't' = 356 g

m_o = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}

Hence, the half life of the sample of phosphorus-32 is 14.28days^{-1}

7 0
4 years ago
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