If the length of AO is three time the length of CO, THE LENGTH OF DC is ...

The time between telephone calls to a cable television service call center follows an exponential distribution with a mean of 1.

Ulleksa [173]

Answer:

0.52763 is the probability that the time between the next two calls will be 54 seconds or less.

0.19285 is the probability that the time between the next two calls will be greater than 118.5 seconds.

Step-by-step explanation:

We are given the following information in the question:

The time between telephone calls to a cable television service call center follows an exponential distribution with a mean of 1.2 minutes.

The distribution function can be written as:

$f(x) = \lambda e^{-\lambda x}\\\text{where lambda is the parameter}\\\\\text{Mean} = \mu = \displaystyle\frac{1}{\lambda}\\\\\Rightarrow 1.2 = \frac{1}{\lambda}\\\\\lambda = 0.84 \\f(x) = 0.84 e^{0.84 x}$

The probability for exponential distribution is given as:

$P( x \leq a) = 1 - e^{\frac{-a}{\mu}}\\\\P(a \leq x \leq b) = e^{\frac{-a}{\mu} -\frac{-b}{\mu}}$

a) P( time between the next two calls will be 54 seconds or less)

$P( x \leq 0.9)\\= 1 - e^{\frac{\frac{-54}{60}}{1.2}} = 0.52763$

0.52763 is the probability that the time between the next two calls will be 54 seconds or less.

b) P(time between the next two calls will be greater than 118.5 seconds)

$p( x > \frac{118.5}{60}) = P(x > 1.975)\\\\ = 1 - P(x \leq 1.975) \\\\= 1 -1+ e^{\frac{-1.975}{1.2}}\\\\= 0.19285$

0.19285 is the probability that the time between the next two calls will be greater than 118.5 seconds.

6 0

3 years ago

Find the distance between the points. (9.7, -2.1), (-3.2, 8.1)

seropon [69]

The answer you are going to be looking for with this question is 16.4. Hope this helps you out a little :)

4 0

3 years ago

Let y be a random variable with p(y) given in the accompanying table. find e(y ), e(1/y ), e(y 2 − 1), and v(y ). y 1 2 3 4 p(y)

Studentka2010 [4]

E[Y] = 0.4·1 + 0.3·2 + 0.2·3 + 0.1·4 = 2 E[1/Y] =0.4·1/1 + 0.3·1/2 + 0.2·1/3 + 0.1·1/4 = 0.4 + 0.15 + 0.0666 + 0.025?0.64 V[Y] =E[Y2]-E[Y]2= (0.4)·12+(0.3)·22+(0.2)·32+(0.1)·42-22= 0.4+1.2+1.8+1.6-4= 5-4 = 1

8 0

4 years ago

as a part of its diet, a pacific seahorse eats about 56 shrimp per week.It eats the same amount each day

Furkat [3]

Answer:

The Pacific seahorse eats 8 shrimp per day

Step-by-step explanation:

The complete question is

As a part of its diet, a Pacific seahorse eats about 56 shrimp per week. It eats the same amount each day.

a) How much shrimp does the Pacific seahorse eat per day?

Complete the statement with the unit rate.

The Pacific seahorse eats _____ shrimp per day.

Part a) How much shrimp does the Pacific seahorse eat per day?

Let

x ---> the number of shrimp that the Pacific seahorse eats per day

we know that

The number of shrimp that the Pacific seahorse eats per day, multiplied by the number of days in a week, must be equal to 56 shrimp

$1\ week=7\ days$

so

The linear equation that represent this situation is equal to

$7x=56$

solve for x

Divide by 7 both sides

$x=8\ shrimp$

therefore

The Pacific seahorse eats 8 shrimp per day

5 0

3 years ago

Given the following quadratic function what’s the value of a, B, and C? f(x)= 3x^2 - 5x -12

s2008m [1.1K]

Answer:

Below.

Step-by-step explanation:

a = 3, b = -5 and c = -12.

6 0

3 years ago