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lisabon 2012 [21]
4 years ago
14

.

Mathematics
1 answer:
timofeeve [1]4 years ago
7 0

Answer:

It will take 150 hours to fill all 3 tanks at a time.

Step-by-step explanation:

Water flows in pipe 1 at a rate of 25,000 gallons per hour.

Other pipe at a rate of 45,000 gallons per hour.

Water leaves the system at a rate of 60,000 gallons per hour.

There are 3 of these tanks and each tank holds 1 million gallons.

Each tank is half full.

So, total capacity of 3 tanks = 3 millions and it is half full.

The water need to be filled = 1.5 millions. At the same time 60,000 gallons of water leaving out.

25,000 x + 45,000 x - 60,000 x = 1.5 millions

70,000x -60,000x = 1500000

10,000x = 1500000

Dividing both sides by 10,000, we get

x = 150 hours

Therefore, it will take 150 hours to fill all 3 tanks at a time.

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Maybe opposite? Not really sure.
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Answer:

Option A.

P=73.4\ units

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see the attached figure with letters to better understand the problem

In this problem we have a triangle with a circle inscribed in it

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step 1

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C.B=A.C-A.B

substitute the given values

C.B=23-14=9\ units

step 2

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Remember that

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step 3

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we know that

E.D=E.C-C.D

substitute the given values

E.D=22.7-9=13.7\ units

step 4

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step 5

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Remember that

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A.F=14\ units

step 6

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P=23+22.7+13.7+14

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6 0
3 years ago
The mass of the gas that exactly fills a 200.ml container? The density of the gas is 5 g/ml
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For this case we can make the following rule of three:
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