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just olya [345]
3 years ago
12

Prove step by step that 5^20-5^19 is an even number with out using a calculator Please can you tell me the steps and why?

Mathematics
1 answer:
hammer [34]3 years ago
8 0

9514 1404 393

Answer:

  factor out 5^19

Step-by-step explanation:

a) Reason from parity:

  both 5^20 and 5^19 are products with only odd numbers (5) as factors. Hence each is an odd number. The difference of odd numbers is always even.

__

b) Factor:

  5^20 -5^19 = 5^19(5 -1) = 5^19×4

This product has an even factor (4), so is even.

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Veseljchak [2.6K]
What are the following rates?
8 0
3 years ago
21x-5=7+17x <br> Write it down step by step please
Nat2105 [25]

Answer: x=3

Step-by-step explanation: Step 1: Simplify both sides of the equation.

21x−5=7+17x

21x+−5=7+17x

21x−5=17x+7

Step 2: Subtract 17x from both sides.

21x−5−17x=17x+7−17x

4x−5=7

Step 3: Add 5 to both sides.

4x−5+5=7+5

4x=12

Step 4: Divide both sides by 4.

\frac{4x}{4} = \frac{12}{4}

So Final Answer: <u>x=3</u>

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<u>If I Helped, Please Mark Me As Brainliest, Have A Great Day :D</u>

4 0
3 years ago
Read 2 more answers
Can someone pls help me!
Sedbober [7]

Answer: y =2x-5

Work:

2x-y=5

-y=-2x+5

-1y/-1 = -2x+5/-1

y =2x-5

5 0
3 years ago
The sum of the measures of two complementary angles is 90°. If one angle measures 24° more than twice the measure of the​ other,
geniusboy [140]
X + y = 90

Let's make 'x' the bigger angle and 'y' the smaller.
X is 24 more than twice y.
x = 24 + 2y

Now plug that into the x of the first equation.
(24 + 2y) + y = 90

Combine like terms.
24 + 3y = 90

Subtract 24 from both sides.
3y = 66

Divide both sides by 3.
y = 22

The measure of the smaller angle is 22°
3 0
3 years ago
Can you guys help me out on this? I'm still learning sign, cosign, and tangent :)
Yakvenalex [24]

Answer:

\sin d = \frac{4}{7} ; \sin e = \frac{\sqrt{33} }{7}

\cos d = \frac{\sqrt{33} }{7} ; \cos e = \frac{4}{7}

\tan d = \frac{4}{\sqrt{33} } ; \tan e = \frac{\sqrt{33} }{4}

Step-by-step explanation:

For a right angled triangle with one of its angle α (alpha) :-

  • \sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \cos \alpha  = \frac{Side \: adjacent \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \tan \alpha  = \frac{Side \: opposite \: to \: \alpha }{Side \: adjacent \: to \: \alpha }

__________________________________________________

According to the question ,

1) When α (alpha) = d

  • \sin d = \frac{4}{7}
  • \cos d = \frac{\sqrt{33} }{7}
  • \tan d = \frac{4}{\sqrt{33} }

2) When α (alpha) = e

  • \sin e = \frac{\sqrt{33} }{7}
  • \cos e = \frac{4}{7}
  • \tan e = \frac{\sqrt{33} }{4}

3 0
3 years ago
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