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4 years ago

For the date on a table does Y very directly with X if it does why in equation for the right variation

Mathematics

1 answer:

Masja [62]4 years ago

8 0

Y is often the variable used to represent the dependent variable in an equation.

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If the areas of two similar decagons are 625 ft^2 and 100 ft^2, what is the ratio of the perimeters of the decagons? tf is a dec

const2013 [10]

$\text{Answer: }\frac{\text{ Perimeter of first decagon}}{\text{ Perimeter of second decagon}}=\frac{5}{2}$

Step-by-step explanation:

Since we have given that

Area of two similar decagons are 625 ft² and 100 ft² ,

As we know the relation of area of similar figures, i.e.

$\frac{\text{ Area of first decagon}}{\text{ area of second decagon}}=\frac{625}{100}=\frac{a^2}{b^2}$

Now, we also know that ,

$\frac{\text{ Perimeter of first decagon}}{\text{ Perimeter of second decagon}}=\frac{a}{b}=\frac{\sqrt{625}}{\sqrt{100}}=\frac{25}{10}=\frac{5}{2}$

Hence,

$\frac{\text{ Perimeter of first decagon}}{\text{ Perimeter of second decagon}}=\frac{5}{2}$

5 0

4 years ago

Find the GCF o the first two terms and the GCF of the last two terms of the polynomial. 5h 3+20h 2+4h+16

riadik2000 [5.3K]

GCF = greatest common factor the GCF of the first two terms is 5h2. GCF of the last two terms is 4.

5 0

3 years ago

Given the speeds of each runner below, determine who runs the fastest.

Lesechka [4]

Answer:

Debbie runs 9 feet per second: 9 ft/s

Jessica runs 1 mile in 440 seconds: 414/50 ft/s = 207/25 ft/s = 8 7/25 ft/s

jesssica runs 131 feet in 10 seconds: since 1 mile = 5280 ft we have 1/470 mi/s = 5280/470 ft/s = 528/47 ft/s = 11 11/47 ft/s

ron runs 603 feet in 1 minute: 547 ft/min = 603/60 ft/s = 201/20 ft/s = 10 1/20 ft/s

Since:

11 11/47 > 10 1/20 > 9 > 8 7/25

Emily runs the fastest.

7 0

3 years ago

What is the answer? I need help like... ASAP

KonstantinChe [14]

Answer:

yeas they are the same shape just different sizes

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Which statement listed below illustrates the reflexive property of congruence

Vlad1618 [11]

Option D:

$\triangle K L M \cong \triangle K L M$

Solution:

Reflexive property of congruence:

Reflexive property of congruence means the geometric figure is congruent to itself.

Option A: If $\triangle K L M \cong \triangle P Q R \text { and } \triangle P Q R \cong \triangle S T U \text { , then } \triangle K LM\cong \triangle S T U$

From the definition of reflexive property, it is not true.

This is transitive property of congruence triangles.

Therefore it is false.

Option B: $\text { If } \triangle KL M \cong \triangle P Q R \text { , then } \triangle P Q R \cong \triangle S T U \text$

From the definition of reflexive property, it is not true.

Therefore it is false.

Option C: $\text { If } \triangle K L M \cong \triangle P Q R \text { , then } \triangle P Q R \cong \triangle K L M$

From the definition of reflexive property, it is not true.

Therefore it is false.

Option D: $\triangle K L M \cong \triangle K L M$

Here, ΔKLM is congruent to itself.

This statement illustrates the reflexive property of congruence for triangles.

Therefore, it is true.

Hence option D is the correct answer.

4 0

3 years ago

Read 2 more answers