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mash [69]
3 years ago
6

Drag the orange point on the cube to change its side length. Then set the base of the pyramid to the same dimensions as a face o

n the cube. Also set the height of the pyramid to the same side length as the cube. Note the volumes of the cube and the pyramid. Record the volumes for a few sets of heights and bases, and then calculate the ratio of the volumes. Be sure the dimensions for the cube and the pyramid are the same in each set. (You might see some discrepancies in the tool due to rounding of decimals.) Round your calculations for the ratio to the hundredths place. The first one has been done for you.
Mathematics
2 answers:
Sergeu [11.5K]3 years ago
4 0

Answer:the link isn’t there can u put the link there

Step-by-step explanation:

charle [14.2K]3 years ago
3 0

Answer:

In order from: <u>Side of Pyramid Base</u> <u> Height of Pyramid</u> <u> Side of Cube</u> <u> Volume of Pyramid</u> and <u>Volume of Cube:</u>

Example 1)     5        5        5        41.6        125.0        0.33

Example 2)    7        7        7        114.3        343.0        0.33

Example 3)    8        8        8        170.7        512.0        0.33

Example 4)    9        9        9        243.1        729.0        0.33

Example 5)    2.5        2.5        2.5        5.2        15.6        0.33

Step-by-step explanation:

this is an example. these are the numbers in the table separated by column in the exact plato answer. i hope this helps a little bit :))

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Step-by-step explanation:

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2 years ago
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Solve the quadratic equation.<br>m^2/15 -3 = 2​
Radda [10]

The answer is 5 \sqrt{3}

<h3>Explanation :</h3>

\frac{ {m}^{2} }{15}  - 3 = 2

\frac{ {m}^{2} }{15}  = 2  + 3

\frac{ {m}^{2} }{15}  = 5

{m}^{2}  = 5 \times 15

{m}^{2}  = 75

m =  \sqrt{75}

m =  \sqrt{25 \times 3}

m =  \sqrt{25}  \times  \sqrt{3}

m = 5 \sqrt{3}

CMIIW

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3 years ago
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