Answer:
The range of the oven is 
Step-by-step explanation:
Consider the provided information.
The internal temperature falls to 20 degrees below the set temperature and turns off when the temperature reaches 5 degrees above the set temperature.
You preheat the oven to 405 degrees before putting a cake in and baking it for an hour at 405.
The internal temperature falls to 20 degrees, therefore the lowest set can be:
405-20=385 degree.
The temperature reaches 5 degrees above the set temperature 405, therefore the upper set is: 405+5=410 degree.
Hence, the temperature will be lying between 385 degree and 410 degree.
This can be written as:
Hence, the range of the oven is
<h3>Factor</h3><h3>√x²+5x+3+2x²+10x-15=0</h3><h3>√x²+2x²+5x+10x+3-15=0</h3><h3>√3x²+15x-12=0</h3><h3>√3x²+(3(5x)+3×-4=0</h3><h3>√3(x²+5x)+3×-4=0</h3><h3>√3(x²+5x-4)=0</h3><h3> </h3>
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Answer:
The completed proof is presented as follows;
The two column proof is presented as follows;
Statements 
Reason
1. 
║ 
, J is the midpoint of 
1. Given
2. ∠IHJ ≅ ∠JLK 2. Alternate angles are congruent
3. ∠IJH ≅ ∠KJL 3. Vertically opposite angles
4. 
≅ 
4. Definition of midpoint
5. ΔHIJ ≅ ΔLKJ 5. By ASA rule of congruency
Step-by-step explanation:
Alternate angles formed by the crossing of the two parallel lines and , by the transversal are equal
Vertically opposite angles formed by the crossing of two straight lines 
and are always equal
A midpoint divides a line into two equal halves
Angle-Side-Angle, ASA rule of congruency states that two triangles ΔHIJ and ΔLKJ, that have two congruent angles, ∠IHJ in ΔHIJ ≅ ∠JLK in ΔLKJ and ∠IJH in ΔHIJ ≅ ∠KJL in ΔLKJ, and that the included sides between the two congruent angles is also congruent ≅ , then the two triangles are congruent, ΔHIJ ≅ ΔLKJ.
