Answer:
it is a horizontal line it has a zero slope
Answer: ![\bold{\dfrac{4}{81d^3}}](https://tex.z-dn.net/?f=%5Cbold%7B%5Cdfrac%7B4%7D%7B81d%5E3%7D%7D)
<u>Step-by-step explanation:</u>
![(3d)^{-4}(4d)\\\\\\=\dfrac{4d}{(3d)^4}\\\\\\=\dfrac{4d}{3^4d^4}\\\\\\=\boxed{\dfrac{4}{81d^3}}](https://tex.z-dn.net/?f=%283d%29%5E%7B-4%7D%284d%29%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B4d%7D%7B%283d%29%5E4%7D%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B4d%7D%7B3%5E4d%5E4%7D%5C%5C%5C%5C%5C%5C%3D%5Cboxed%7B%5Cdfrac%7B4%7D%7B81d%5E3%7D%7D)
Answer is : f^-1 (x)=-2x/3+1
Answer:
286 mm²
Step-by-step explanation:
A trapezium is given with ,
- Parallel sides = 24mm , 28 mm
- Height = 11mm .
<u>The </u><u>area </u><u>is </u><u>given</u><u> by</u><u> </u><u>:</u><u>-</u><u> </u>
Area = 1/2 ( b₁ + b ₂) × h
Area = 1/2 ( 24 + 28)×11 mm²
Area = 1/2 × 52× 11mm²
Area = 286 mm²
<h3>
<u>Hence </u><u>the</u><u> </u><u>area </u><u>of</u><u> the</u><u> </u><u>trapezium</u><u> </u><u>is </u><u>2</u><u>8</u><u>6</u><u> </u><u>mm²</u><u>.</u></h3>
Answer: Solve for the specified variables
Step-by-step explanation:
1. w= A/l
2. d=C/pi
3. s=v-gt
4. y= 5/2x-11/2
5. P^2= P^1V^1 / P^2 Put ^ as lowercase as shown, can't find symbol on my keboard T.T
6. W= Ke2g / V^2
7. h= V / 2/3 pi r^2
8. n=2S/a+k
9. S=A/pi r - r (not 100% sure on that one)
10. r= E/I-R
11. h= E-1/2mv^2/mg
12. a=K+5b/b+3
13. c=ab/b+a
Wooh, finally finished all that. Hope I didn't make any mistakes. Have a great day!