Write the equation of the line passing through the point (2,-1) with a slope of -3
2 answers:
We have a slope of -3 and a point of (2,-1) so this line can be expressed as:
slope intercept form: y=mx+b where m=slope and b=y-intercept...
y=-3x+b, using point (2,-1) we can solve for b
-1=-3(2)+b
-1=-6+b
b=5 so
y=-3x+5
.....
We can also express this in point slope form: (y-y1)=m(x-x1) we know m=-3 and (x1,y1)=(2,-1)
(y+1)=-3(x-2)
....
Finally we can express the line is standard form: ax+by=k
If we look at the y=mx+b that we had earlier we can simply rearrange it into standard form...
y=-3x+5 add 3x to both sides and we are done :P
3x+y=5
Y= 2x-3 i think, but i may be wrong
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