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lara [203]
2 years ago
14

Alexander is a stockbroker. He earns 13​% commission each week. Last​ week, he sold ​$5,300 worth of stocks. How much did he mak

e last week in​ commission? If he averages that same amount each​ week, how much did he make in commission in​ 2011?
Last​ week, he made ​$689 in commission.
In​ 2011, he made ​$_____ in commission. Answer for missing box.
Mathematics
2 answers:
Nataliya [291]2 years ago
7 0
Byrhjjgdwsghxswcjj gj Ibhdf
yKpoI14uk [10]2 years ago
5 0

Answer:

$30,420

Step-by-step explanation:

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What are the degree and leading coefficient of the polynomial of 12u3 -8 + 23u
irga5000 [103]

Answer:

Degree: 3

Leading Coefficient: 12

Step-by-step explanation:

Find the highest power to determine the degree, in this case it's 3. Then identify the term with the highest power (12u^3) to find the leading coefficient.

So, because 3 is the largest and only power in this equation, it is the degree. 12u^3 is the leading term (term containing the highest degree) and 12 is the coefficient attatched to the term. Hope that helped!

4 0
3 years ago
The variance can never bea.zerob.larger than the standard deviationc.negatived.smaller than the standard deviation
MrRa [10]

Answer:

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

Step-by-step explanation:

We need to remember that the variance is a measure of dispersion for a dataset respect to a measure of central tendency called the mean. The mean is defined as:

\bar x = \frac{\sum_{i=1}^n X_i}{n}

And the population mean is given by:

\mu= \frac{\sum_{i=1}^n X_i}{N}

The population variance is defined by:

\sigma^2 = \frac{\sum_{i=1}^n (X_i -\mu)^2}{N}

And the sample variance is defined as:

s^2= \frac{\sum_{i=1}^n (X_i -\bar x)}{n-1}

Now if we analyze the options we have this:

a.zero

False, if all the values are the same then the mean would be the same to the values and the difference between each value and the mean would 0 and indeed the variance would be 0.

b.larger than the standard deviation

False, if the population standard deviation is \sigma=2 then the variance would be \sigma^2 = 4 and as we can see is higher than the standard deviation

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

d.smaller than the standard deviation

False, if the population standard deviation is \sigma=0.1 then the variance would be \sigma^2 = 0.01 and as we can see is lower than the standard deviation

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3 years ago
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Answer:

each cup cost 1.25 on Tuesday

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