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Fynjy0 [20]
3 years ago
5

Kayla has taken six history quizzes so far, earning the following scores. 7, 8, 8, 8, 10, 9 Which measure of central tendency wo

uld Kayla want her teacher to use to make her grades sound as high as possible?
A.mean

B.median

C.mode

D.range
Mathematics
2 answers:
kozerog [31]3 years ago
7 0
The awnser to your question is the median
Jobisdone [24]3 years ago
5 0

Answer:

B.median

Step-by-step explanation:

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The ratio of the lengths of the two legs of a right triangle is 3:4
Snowcat [4.5K]

<em>Greetings from Brasil... </em>

Check Attachment!!!

According to the statement of the question, we have:

a/b = 3/4

<em>Note that according to the attached figure, </em><em>b > a</em><em>, then the correct proportion will be </em><em>a</em><em> to </em><em>3</em><em>, as well as </em><em>b</em><em> to </em><em>4</em><em>, because </em><em>b > a</em><em> and </em><em>4 > 3</em>

Isolating a and b:

a = 3b/4

b = 4a/3

From Pythagoras:

h² = a² + b² - as a = 3b/4 and b = 4a/3, so

<h3>b = 4h/5</h3><h3>a = 6h/5</h3>

For Area:

A = b.a/2

as b = 4h/5 and a = 6h/5, so

<h3>A = 12h/25</h3>

4 0
2 years ago
Find the product.<br><br> y4 · y6
Vanyuwa [196]

Answer:

y^{10}

Step-by-step explanation:

I am assuming that you mean y^4*y^6.

y^4*y^6\\\text {Apply the product rule: } a^n*a^m =a^{n+m}\\4 + 6 = 10\\\text {Therefore,}\\\boxed {y^4*y^6 = y^{10}}

<em>Brainilest Appreciated.</em>

4 0
3 years ago
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The function ƒ(x ) = -3x + 5 is represented by which set of ordered pairs?
ozzi

Answer:

The correct answer is the first set {(-1, 8), (0, 5), (2, -1), (3, -4)}

Step-by-step explanation:

In order to determine if the set works, input each ordered pair to see if the statement ends up true. The first two ordered pairs are done below.

(-1, 8)

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8 = -3(-1) + 5

8 = 3 + 5

8 = 8 (TRUE)

(0, 5)

f(x) = -3x + 5

5 = -3(0) + 5

5 = 0 + 5

5 = 5 (TRUE)

6 0
3 years ago
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Ipatiy [6.2K]

Answer:

yes

Step-by-step explanation:

4 0
3 years ago
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Hi! -2x + y = -11 4x + 4y = 4 System by substitution!!!
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Answer:

Point Form:

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