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podryga [215]
3 years ago
6

Evaluate 3{5+3[10+4•8]}​

Mathematics
1 answer:
Hatshy [7]3 years ago
8 0
The answer to your equation is 1008
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Alenkinab [10]

everything except the last two, I think.

3 0
3 years ago
Alistair has a rectangular picture measuring 8 inches by 7 inches. He makes a frame for the picture, shown by the shaded area in
nydimaria [60]
<span>You are given a rectangular picture measuring 8 inches by 7 inches. Also, Alistair wants this to be framed and that the total area is 34 square inches. The width of the frame is x inches. To solve the dimension of the frame with value of x we have:

We have to assume that x here will be equal to all sides of the frame and so, using the area of the rectangle, we can model the equation like this:
A = LW (where A is the area, L is the length and W is the width)
36 = (8 - x)(7 - x)
36 = 56 - 8x - 7x + x</span>²
<span>x</span>² - 15x +20 = 0 → model of our equation and in quadratic form

x² - 15x + 20 = 0
using a calculator, x = 1.48 inches
<span>
3.Use the equation you created in part A to find the width of the picture frame</span>
7 0
3 years ago
Free points: this is because of all the kindness I have seen on brainly:
VashaNatasha [74]
The answer is 35450 :)
8 0
3 years ago
Read 2 more answers
HELP, I'M GIVING A GOOD AMOUNT OF POINTS
jekas [21]

Answer:

I need to know what the question asks

Step-by-step explanation:

5 0
3 years ago
You are situated 300 feet from the base of Tower Glitz Plaza watching an external elevator descend down the side of the building
nordsb [41]

Answer:

18.66 ft/s

Step-by-step explanation:

The distance between you and the elevator is given by:

h=\sqrt{x^2+y^2}

The rate of change for the distance between you and the elevator is given by:

\frac{dh}{dt}=\frac{dh}{dy}*\frac{dy}{dt}

-16=\frac{dh}{dy}*\frac{dy}{dt}

\frac{dh}{dy}=\frac{d}{dy} (\sqrt{x^2+y^2})\\

Applying the chain rule:

u=x^2+y^2\\\frac{dh}{dy}=\frac{d\sqrt u}{du} *\frac{du}{dy}\\\frac{dh}{dy}=\frac{1}{2\sqrt u} *2y\\\frac{dh}{dy}=\frac{y}{\sqrt {(x^2+y^2)}}

Therefore, at x=300 and y = 500, dy/dt is:

-16=\frac{y}{\sqrt {(x^2+y^2)}}*\frac{dy}{dt}\\-16=\frac{500}{\sqrt {(300^2+500^2)}}*\frac{dy}{dt}\\\frac{dy}{dt}=-18.66\ ft/s

The elevator is descending at 18.66 ft/s.

7 0
3 years ago
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