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Sergio [31]
3 years ago
5

Q5: The probability that event A occurs is 5/7 and the probability that event B occurs is 2/3 . If A and B are independent event

s, what is the probability that A and B both occur?
Mathematics
1 answer:
bekas [8.4K]3 years ago
7 0

Answer:

P(A \cap B)

And we can use the following formula:

P(A \cap B)= P(A)* P(B)

And replacing the info we got:

P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476

Step-by-step explanation:

We define two events for this case A and B. And we know the probability for each individual event given by the problem:

p(A) = \frac{5}{7}

p(B) = \frac{2}{3}

And we want to find the probability that A and B both occurs if A and B are independent events, who menas the following conditions:

P(A|B) = P(A)

P(B|A) = P(B)

And for this special case we want to find this probability:

P(A \cap B)

And we can use the following formula:

P(A \cap B)= P(A)* P(B)

And replacing the info we got:

P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476

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Answer:

(-1, -2.5)

Step-by-step explanation:

the midpoint of a segment is (\frac{x1+x2}{2} ,\frac{y1+y2}{2}), given points (x1, y1) and (x2, y2)

midpoint=(\frac{-9+7}{2}, \frac{3-8}{2} ) = (\frac{-2}{2}, \frac{-5}{2}  ) = (-1, -2.5)

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Charlie invests £1200 at 3.5% per annum compound interest.
lbvjy [14]

Answer:

<h2>£1,330.46</h2>

Step-by-step explanation:

Using the compound interest formula A = P(1+\frac{r}{n} )^{nt}

A = amount compounded after n years

P = principal (amount invested)

r = rate (in %)

t = time (in years)

n = time used to compound the money

Given P =  £1200., r = 3.5%, t = 3years, n = 1 year(compounded annually)

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Value of Charlie's investment after 3 years is £1,330.46

6 0
3 years ago
I do not get what this means
gladu [14]
This means that with certain types of data, mean, median, or mode may be more effective for analysis. 
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