All categories

2 years ago

Write the hourly wage 15 dollars an hour as a fraction

Mathematics

1 answer:

amid [387]2 years ago

4 0

it can be written like this, hope this helps: $15/hour <3

You might be interested in

URGENT PLS HELP

Dahasolnce [82]

Align the horizontal edge of the protractor with the base of the triangle. Place the center point of the protractor on the vertex of the angle. Follow the side of the triangle until it reaches the angle measurement mark. Note the measurement.

7 0

3 years ago

3) Determne the largest multiple of 9 less than 200

BaLLatris [955]

Answer:

i think 22

Step-by-step explanation:

9*22=198

8 0

3 years ago

Jade and Eliza went shopping at a mall. Jade spent $10 more than 5 times the amount that Eliza spent. Jade spent a total of $150

DaniilM [7]

Answer:

140

Step-by-step explanation:

Let total money spent by Eliza's be represented as x

Five times amount Eliza spent = 5x and total amount spent by Jade is $150

So it will be $10+ 5x =$150

5x= 150- 10

5x= 140

x = 140÷5

x= 28

........................

So therefore Eliza's amount spent = $28 and

5x$28 = $140

Jade spent $10 more equals $10+$140= $150(Total money spent by Jade).

8 0

3 years ago

A sample of a radioactive substance decayed to 97% of its original amount after a year. (Round your answers to two decimal place

Andrej [43]

Answer:

a) The half life of the substance is 22.76 years.

b) 5.34 years for the sample to decay to 85% of its original amount

Step-by-step explanation:

The amount of the radioactive substance after t years is modeled by the following equation:

$P(t) = P(0)(1-r)^{t}$

In which P(0) is the initial amount and r is the decay rate.

A sample of a radioactive substance decayed to 97% of its original amount after a year.

This means that:

$P(1) = 0.97P(0)$

Then

$P(t) = P(0)(1-r)^{t}$

$0.97P(0) = P(0)(1-r)^{0}$

$1 - r = 0.97$

$P(t) = P(0)(0.97t)^{t}$

(a) What is the half-life of the substance?

This is t for which P(t) = 0.5P(0). So

$P(t) = P(0)(0.97t)^{t}$

$0.5P(0) = P(0)(0.97t)^{t}$

$(0.97)^{t} = 0.5$

$\log{(0.97)^{t}} = \log{0.5}$

$t\log{0.97} = \log{0.5}$

$t = \frac{\log{0.5}}{\log{0.97}}$

$t = 22.76$

The half life of the substance is 22.76 years.

(b) How long would it take the sample to decay to 85% of its original amount?

This is t for which P(t) = 0.85P(0). So

$P(t) = P(0)(0.97t)^{t}$

$0.85P(0) = P(0)(0.97t)^{t}$

$(0.97)^{t} = 0.85$

$\log{(0.97)^{t}} = \log{0.85}$

$t\log{0.97} = \log{0.85}$

$t = \frac{\log{0.85}}{\log{0.97}}$

$t = 5.34$

5.34 years for the sample to decay to 85% of its original amount

8 0

3 years ago

Simplify (9^2)1/3 using rational exponents

Alborosie

Answer:

Step-by-step explanation:

(9^2)^(1/3) = 9^(2 * 1/3) = 9^(2/3)

8 0

2 years ago

Read 2 more answers