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3 years ago

Kelly walked 3 miles.Abby walk 3/4 of a mile how far did they walk in all

Mathematics

1 answer:

timofeeve [1]3 years ago

8 0

Answer:

3 3/4

Step-by-step explanation:

Add the two numbers:

3 + 3/4 = 3 3/4

3 3/4 is the amount walked in all.

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Plz Help ASAP<br>plz help me with #2. <br>Plz I'm begging u!!!!!!

Sergeu [11.5K]

$230 divided by 1/4 = 57.5

8 0

3 years ago

Write a real world problem for: 80-3x=53

Oxana [17]

Answer:

Sam had 80 dollars in his pocket. He was feeling generous, so he handed out equal amount of money to each of his friends. After he handed out the money, he had 53 dollars left. How much did Sam give out to each one of his friends?

Step-by-step explanation:

In this real-world problem, the money he had at the beginning resembles the 80 in the equation. The -3x is the money he gives out to each of his friends. The 53 on the right-hand side is the money he has left after he gives the money away.

6 0

3 years ago

Which expression is equivalent to *picture attached*

DiKsa [7]

Answer:

The correct option is;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$

Step-by-step explanation:

The given expression is presented as follows;

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right )$

Which can be expanded into the following form;

$\sum\limits _{n = 1}^{50} \left (4\cdot n^2 + 3 \cdot n\right ) = 4 \times \sum\limits _{n = 1}^{50} \left n^2 + 3 \times\sum\limits _{n = 1}^{50} n$

From which we have;

$\sum\limits _{k = 1}^{n} \left k^2 = \dfrac{n \times (n+1) \times(2n+1)}{6}$

$\sum\limits _{k = 1}^{n} \left k = \dfrac{n \times (n+1) }{2}$

Therefore, substituting the value of n = 50 we have;

$\sum\limits _{n = 1}^{50} \left k^2 = \dfrac{50 \times (50+1) \times(2\cdot 50+1)}{6}$

$\sum\limits _{k = 1}^{50} \left k = \dfrac{50 \times (50+1) }{2}$

Which gives;

$4 \times \sum\limits _{n = 1}^{50} \left n^2 = 4 \times \dfrac{n \times (n+1) \times(2n+1)}{6} = 4 \times \dfrac{50 \times (50+1) \times(2 \times 50+1)}{6}$

$3 \times\sum\limits _{n = 1}^{50} n = 3 \times \dfrac{n \times (n+1) }{2} = 3 \times \dfrac{50 \times (51) }{2}$

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right ) = 4 \times \dfrac{50 \times (50+1) \times(2\times 50+1)}{6} +3 \times \dfrac{50 \times (51) }{2}$

Therefore, we have;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$ .

4 0

2 years ago

Please do #4 It’s it the one on the bottom

spin [16.1K]

We need to graph this equation:

$16x+2y=300$

Its solutions are the points through which it graph passes. Since it's a linear equation its graph is a straight line and we only need two of its points to draw it. But before graphing let's re-write the equation. We can substract 16x from both sides:

$\begin{gathered} 16x+2y=300 \\ 16x+2y-16x=300-16x \\ 2y=300-16x \end{gathered}$

And we divide both sides by 2:

$\begin{gathered} \frac{2y}{2}=\frac{300-16x}{2}=\frac{300}{2}-\frac{16x}{2} \\ y=150-8x \end{gathered}$

So now with this equation if we pick two random x values we'll get their corresponding y values. This way we'll find two points that are part of the graph which is the line that passes through both. We can begin with x=0:

$y=150-8\cdot0=150$

So the first point is (0,150). Then we can take x=10 and we get:

$y=150-8\cdot10=150-80=70$

So the second point is (10,70). Then the graph is the line that passes through points (0,150) and (10,70). In order to represent it

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1 year ago

Write the same ratio using another form A:B vs A to B

Firdavs [7]

A over B like a.fraction

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2 years ago

Read 2 more answers