Area of sector is 17.584 meters
<em><u>Solution:</u></em>
Given that we have to find the approximate area of a sector given O= 56 degrees with a diameter of 12m
Diameter = 12 m
Radius = Diameter / 2 = 6 m
An angle of 56 degrees is the fraction
of the whole rotation
A sector of a circle with a sector angle of 56 degrees is therefore also the fraction
of the circle
The area of the sector will therefore also be
of the area

Thus area of sector is 17.584 meters
The intensity of an earthquake with a magnitude of 2 is 100 times greater than the intensity of an a standard earthquake .
<h3>
What is magnitude of earthquake
?</h3>
Magnitude of earthquake is the measure of the size of origin of the earthquake. The magnitude of the earthquake keeps the same value for each place.
An earthquake with a magnitude of about 2. 0 or less is called a micro-earthquake and not felt usually.The intensity of an earthquake with a magnitude of 2.
Let the intensity of this earthquake is <em>n </em>times greater than the intensity of an a standard earthquake. Thus the intensity of standard earthquake can be given as,

If the magnitude would be 3 then the intensity would be,

It would be 1000 times greater than the standard earthquake and so on.
Thus, the intensity of an earthquake with a magnitude of 2 is 100 times greater than the intensity of an a standard earthquake .
Learn more about the magnitude of earthquake here;
brainly.com/question/18109453
Answer:
Step-by-step explanation:
diameter = 8 cm
radius = 8/2 = 4 cm
Area of circle = πr²
= 3.14*4*4 = 50.24 cm²
It’s a grouping of linear(straight line)equations that deal with the same variables. Hope that helped?
By geometrical inspection we have:
M4 = 30
Then the angle M6 can be determined from the fact that you have a rectangle triangle (345) that has an angle of 90 and another of 30. The missing angle measures:
180-90-30 = 60 = M3
Then to find M6 we have
M3 + 60 + M6 = 180
M6 = 180-60-M3
M6 = 180-60-60
M6 = 60
answer:
M4 = 30
M6 = 60