A point P on the line segment GK may be parametrically represented as
![P = (1-t)G + tK](https://tex.z-dn.net/?f=P%20%3D%20%281-t%29G%20%2B%20tK)
t is a real parameter which controls where on the segment P is. t=0 means P=G, t=1 means P=K. We're interested in the t that gives a 3:2 ratio for PG:PK. That's closer to K so t>1/2. t=3/(3+2) = 3/5.
![P=(1-3/5)(1,2) + (3/5)(8,12) = (2/5,4/5)+(24/5,36/5)=(26/5,40/5)=(26/5,8)](https://tex.z-dn.net/?f=P%3D%281-3%2F5%29%281%2C2%29%20%2B%20%283%2F5%29%288%2C12%29%20%3D%20%282%2F5%2C4%2F5%29%2B%2824%2F5%2C36%2F5%29%3D%2826%2F5%2C40%2F5%29%3D%2826%2F5%2C8%29)
Answer: (26/5, 8)
3087810 is 15f+5g+45 in standard form
2 = X = -1
2
2. 2(4x+2) - (x-4) = 3(x+2)
Expand tge expression
= 8x + 4 -x +4 = 3x + 6
CLT ( Combine like terms)
= 7x + 8 = 3x + 6
Rearrange the terms
7x - 3x = 6 - 8
CLT
4x = -2
Divide both sides by 4
x = -2
4
x = -1
2
Answer:
t = 36
Step-by-step explanation:
If one of the roots is "a", the equation can be factored as ...
(5x -a)(x -a) = 0
5x^2 -6ax +a^2 = 0
Comparing terms to the given equation, we see that ...
-6ax = -36x
a = 6 . . . . . . . . divide by -6
Then ...
a^2 = t
36 = t . . . . . . . substitute 6 for a
_____
The roots are 6 and 6/5.
to do this all you have to do is subtract 9.185 form 10 to get .815ft