27+3x-31=20
-4+3x=20
+4 +4
3x=24
X=8
1) Our marbles will be blue, red, and green. You need two fractions that can be multiplied together to make 1/6. There are two sets of numbers that can be multiplied to make 6: 1 and 6, and 2 and 3. If you give the marbles a 1/1 chance of being picked, then there's no way that a 1/6 chance can be present So we need to use a 1/3 and a 1/2 chance. 2 isn't a factor of 6, but 3 is. So we need the 1/3 chance to become apparent first. Therefore, 3 of the marbles will need to be one colour, to make a 1/3 chance of picking them out of the 9. So let's say 3 of the marbles are green. So now you have 8 marbles left, and you need a 1/2 chance of picking another colour. 8/2 = 4, so 4 of the marbles must be another colour, to make a 1/2 chance of picking them. So let's say 4 of the marbles are blue. We know 3 are green and 4 are blue, 3 + 4 is 7, so the last 2 must be red.
The problem could look like this:
A bag contains 4 blue marbles, 2 red marbles, and 3 green marbles. What are the chances she will pick 1 blue and 1 green marble?
You should note that picking the blue first, then the green, will make no difference to the overall probability, it's still 1/6. Don't worry, I checked
2) a - 2% as a probability is 2/100, or 1/50. The chance of two pudding cups, as the two aren't related, both being defective in the same packet are therefore 1/50 * 1/50, or 1/2500.
b - 1,000,000/2500 = 400
400 packages are defective each year
Answer:
Step-by-step explanation:
sum of ratio=3+6=9
Jeff invest=3/9×146,000=146000/3=48666 2/3 $
Trudy invest=6/9×146,000=292,000/3=97,333 1/3 $
D. All irrational numbers are rational numbers.
I attached the diagram my teacher showed us when we learned about this. I think it makes it a lot less confusing.
Hope this helps :)
Answer:
x = -5
Step-by-step explanation:
First distribute the 5 on the right side of the equation.
10x - 35 = 15x - 10
Then subtract 10x on each side
-35 = 5x - 10
Then add 10 on each side
-25 = 5x
Divide 5 on each side to get x
-25 / 5 = -5
I hope this helps! :)