I need to know how to solve this problem using the substitution method for a linear system
1 answer:
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The cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7
<em><u>Solution:</u></em>
Let "c" be the cost of 1 chocolate cake
Let "v" be the cost of 1 vanilla cake
<em><u>Jenny sold 14 chocolate cakes and 5 vanilla cakes for 119 dollars</u></em>
Therefore, we can frame a equation as:
14 x cost of 1 chocolate cake + 5 x cost of 1 vanilla cake = 119
14c + 5v = 119 ------- eqn 1
<em><u>Natalie sold 10 chocolate cakes and 10 vanilla cakes for 130 dollars</u></em>
Therefore, we can frame a equation as:
10 x cost of 1 chocolate cake + 10 x cost of 1 vanilla cake = 130
10c + 10v = 130 -------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
Multiply eqn 1 by 2
28c + 10v = 238 ------ eqn 3
<em><u>Subtract eqn 2 from eqn 3</u></em>
28c + 10v = 238
10c + 10v = 130
( - ) --------------------------
18c = 108
c = 6
<em><u>Substitute c = 6 in eqn 1</u></em>
14(6) + 5v = 119
84 + 5v = 119
5v = 119 - 84
5v = 35
v = 7
Thus cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7