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shtirl [24]
4 years ago
12

In the triangle below x=? Degrees. Round to the nearest tenth.

Mathematics
1 answer:
Lina20 [59]4 years ago
4 0

Answer:

40 °

Step-by-step explanation:

tan(x)=\frac{8}{10} \\x=tan^{-1} (\frac{8}{10} )

x=38.65980825

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What equation is being represented by this line?
faust18 [17]

Answer:

The equation that represented by the line is y = -x + 2

Step-by-step explanation:

The slope-intercept form of the linear equation is y = m x + b, where

  • m is the slope of the line
  • b is the y-intercept (value y at x = 0)

The rule of the slope is m = \frac{y2-y1}{x2-x1} , where  

  • (x1, y1) and (x2, y2) are two points on the line

<em>From the given figure  </em>

∵ The line passes through points (2, 0) and (0, 2)

∴ x1 = 2 and y1 = 0  

∴ x2 = 0 and y2 = 2  

→ Substitute them in the rule of the slope to find it

∵ m =  \frac{2-0}{0-2}=\frac{2}{-2}=-1

∴ m = -1  

→ Substitute it in the form of the equation above

∵ y = -1(x) + b

∴ y = -x + b  

∵ b is value y at x = 0  

∵ At x = 0, y = 2

∴ b = 2

→ Substitute it in the equation above

∴ y = -x + 2

∴ The equation that represented by the line is y = -x + 2

6 0
3 years ago
Need helllllllllllpppppppppppppppp
zhannawk [14.2K]
39? I think it is..........
6 0
3 years ago
A football thrown by a quarterback follows a path given by hx=-0.0095x2+x+7, where h is the height of the ball in feet and x is
Wewaii [24]

Answer:

The ball can be knocked down at a horizontal distance of 3.09 feet or 102.17 feet from the marshal.

Step-by-step explanation:

We have the function that represents the height h (x) of the ball h(x) = -0.0095x^2 + x + 7

Where x is the horizontal distance of the ball.

We want to find the horizontal distance the ball is at (horizontal distance between the field marshal and the ball) when it is at a height of 10 feet.

To do this, we must do h (x) = 10

10 = -0.0095x^2 + x + 7\\0 = -0.0095x^2 + x -3

Now we must solve the second degree equation. For this we use the formula of the resolvent:

\frac{-b + \sqrt{b ^ 2 - 4 * a * c}}{2a}

       and

\frac{-b - \sqrt{b ^ 2 - 4 * a * c}}{2a}


\frac{-1 + \sqrt{1 ^ 2 - 4 * (- 0.0095)(-3)}} {2 (-0.0095)} = 3.09 ft

  and

\frac{-1 - \sqrt{1 ^ 2 - 4 * (- 0.0095)(-3)}} {2 (-0.0095)} = 102.17ft


Then, the ball can be knocked down at a horizontal distance of 3.09 feet or 102.17 feet from the marshal.

7 0
4 years ago
Which algebraic is demonstrated in the equation below?<br><br> 5÷3(2x-7)=5+6x-21
vivado [14]
That is an example of the use of the distributive property of multiplication. However, you wrote the problem incorrectly... the sign following 5 changed from ÷ to +
7 0
3 years ago
a quarterback is sacked for a loss of 5 yards.On the next day his team loses 15 yards.Then the team gains 12 yards on the third
Veronika [31]

Assume it is first down and ten in this problem. When you lose 5 yards on the sack, you are 5 yards further away. So now, it is second and 15. Then, they lose another 15 yards, so it's now third and 30. The final play is that they gain 12 yards, meaning after all the plays it is fourth down and eighteen yards to go.

In math symbols, 0 is where the first down marker is. You start at -10.

First play, the sack: -10 - 5 = -15

Second play: -15 - 15 = -30

Third play: -30 + 12 = -18.

Looks like you have to punt on fourth down :)

8 0
4 years ago
Read 2 more answers
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