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yuradex [85]
3 years ago
5

Suppose that a manufacturer is testing one of its machines to make sure that the machine is producing more than​ 97% good parts

​(H0​: p=0.97 and Ha: p​ > 0.97). The test results in a​ p-value of 0.102. In​ reality, the machine is producing​ 99% good parts. What probably happens as a result of our​ testing?
a. We fail to reject H0,making a Type II error.
b. We fail to reject H0, making a Type I error.
c. We correctly reject H0.
d. We reject H0, making a Type I error.
e. We correctly fail to reject H0.
Mathematics
1 answer:
Masja [62]3 years ago
6 0

Answer:

a. We fail to reject H0,making a Type II error.

Step-by-step explanation:

H0: Null Hypothesis: p = 0.97  HA: Alternative Hypothesis: p > 0.97

P- Value = 0.102  if \alpha = 0.05.  therefore P-value > \alpha . we have therefore failed to reject the null hypothesis H0.

The following rule states that when we reject H0, H0 is true for Type I error and Ha is true for correct decision. When we fail to reject H0, H0 is true for correct decision and Ha is true for Type II error.

Based on the above and having failed to reject a false null hypotheses, Type II error is the failure to reject a false null hypothesis, thus making a Type II error. Therefore when we fail to reject H0, we make a Type II error.

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Rufina [12.5K]

Answer:

What is the GCF of 36 and 84?

Find the prime factorization of 36.

Find the prime factorization of 84. 84 = 2 × 2 × 3 × 7.

To find the GCF, multiply all the prime factors common to both numbers: Therefore, GCF = 2 × 2 × 3.

GCF = 12.

The common factors of 84 are 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, and 84. We can get all the factors using the prime factorization method.

Step-by-step explanation:

7 0
2 years ago
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Miriam makes two and a fourth gallons of punch for a school event. How many 4‐ounce servings of punch can she serve?
cricket20 [7]
Don't lie about your age and 32oz+(2*128)=32oz+256=288oz
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3 years ago
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In arithmetic sequence tn find: S10, if t2=5 and t8=15
makkiz [27]

Given:

\bold{t_2=5}\\\\\bold{t_8=15}\\\\

To find:

\bold{T_n=?}\\\\\bold{S_{10}=?}

Solution:

\to \bold{t_2=5}\\\\  \bold{a+d=5} \\\\  \bold{a=5-d} ................(i)\\\\ \to \bold{t_8=15}\\\\ \bold{a+ 7d=15}.................(ii)\\\\

Putting the equation (i) value into equation (ii):

\to \bold{5-d+7d=15}\\\\\to \bold{5+6d=15}\\\\\to \bold{6d=15-5}\\\\\to \bold{6d=10}\\\\\to \bold{d=\frac{10}{6}}\\\\\to \bold{d=\frac{5}{3}}\\\\

Putting the value of (d) into equation (i):

\to \bold{a=5-\frac{5}{3}}\\\\\to \bold{a=\frac{15-5}{3}}\\\\\to \bold{a=\frac{10}{3}}\\\\

Calculating the \bold{t_n :}

\to \bold{t_n=a+(n-1)d}\\\\\to \bold{t_n=\frac{10}{3}+(n-1)\frac{5}{3}}\\\\\to \bold{t_n=\frac{10}{3}+\frac{5}{3}n-\frac{5}{3}}\\\\\to \bold{t_n=\frac{10}{3}-\frac{5}{3} +\frac{5}{3}n}\\\\\to \bold{t_n=\frac{10-5}{3} +\frac{5}{3}n}\\\\\to \bold{t_n=\frac{5}{3} +\frac{5}{3}n}\\\\ \to \bold{t_n=\frac{5}{3}(1+n)}\\\\

Formula:

\bold{S_n = \frac{n}{2}[2a + (n - 1)d ] }\\

Calculating the \bold{S_{10}} :

\to \bold{S_{10} = \frac{10}{2}[2\frac{10}{3} + (10- 1)\frac{5}{3} ] }\\\\\to \bold{S_{10} = 5[\frac{20}{3} + (9)\frac{5}{3} ] }\\\\\to \bold{S_{10} = 5[\frac{20}{3} + 9 \times \frac{5}{3} ] }\\\\\to \bold{S_{10} = 5[\frac{20}{3} + 3\times 5 ] }\\\\\to \bold{S_{10} = 5[\frac{20}{3} + 15 ] }\\\\\to \bold{S_{10} = 5[\frac{20+ 45}{3} ] }\\\\\to \bold{S_{10} = 5[\frac{65}{3} ] }\\\\\to \bold{S_{10} = 5 \times \frac{65}{3}  }\\\\\to \bold{S_{10} =  \frac{325}{3}  }\\\\\to \bold{S_{10} =108.33 }

Therefore, the final answer is  " \bold{\frac{5}{3}(1+n)\ and\ 108.33}"

Learn more:

brainly.com/question/11853909

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Answer:

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Step-by-step explanation:

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100 {v}^{2}  - 324

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We factor the GCF to get

4(25 {v}^{2}  - 81)

We rewrite the expression within the parenthesis as difference of two squares.

4(( {5v})^{2}  -  {9}^{2} )

Recall that: a²-b²=(a-b)(a+b)

This implies that

4(5v + 9)(5v - 9)

6 0
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Yes, Ayden painted 15 square meters more.

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