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V125BC [204]
3 years ago
7

If AB = 8 and BC = 24, then AC = If AB = 17 and AC = 68, then BC =

Mathematics
1 answer:
Kryger [21]3 years ago
6 0

Answer:

(i) The length of AC is 32 units, (ii) The length of BC is 51 units.

Step-by-step explanation:

(i) Let suppose that AB and BC are collinear to each other, that is, that both segments are contained in the same line. Algebraically, it can be translated into this identity:

AC = AB + BC

If we know that AB = 8 and BC = 24, then:

AC = 8 + 24

AC = 32

The length of AC is 32 units.

(ii) Let suppose that AB and AC are collinear to each other, that is, that both segments are contained in the same line. Algebraically, it can be translated into this identity:

AC = AB + BC

BC = AC - AB

If we know that AC = 68 and AB = 17, then:

BC = 68-17

BC = 51

The length of BC is 51 units.

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Answer:

\frac{-11}{25}+\frac{-27}{25}i given you are asked to simplify

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Step-by-step explanation:

You have to multiply the numerator and denominator by the denominator's conjugate.

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When you multiply conjugates, you just have to multiply first and last.

(a+bi)(a-bi)

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So we are multiplying top and bottom of your fraction by (-3+4i):

\frac{-3+5i}{-3-4i} \cdot \frac{-3+4i}{-3+4i}=\frac{(-3+5i)(-3-4i)}{(-3-4i)(-3+4i)}

So you will have to use the complete foil method for the numerator. Let's do that:

(-3+5i)(-3+4i)

First: (-3)(-3)=9

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Inner: (5i)(-3)=-15i

Last: (5i)(4i)=20i^2=20(-1)=-20

--------------------------------------------Combine like terms:

9-20-12i-15i

Simplify:

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Now the bottom (-3-4i)(-3+4i):

F(OI)L (we are skipping OI)

First:-3(-3)=9

Last: -4i(4i)=-16i^2=-16(-1)=16

---------------------------------------------Combine like terms:

9+16=25

So our answer is \frac{-11-27i}{25}{/tex] unless you want to seprate the fraction too:[tex]\frac{-11}{25}+\frac{-27}{25}i

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