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2 years ago

Pls help me and show work pls

Mathematics

1 answer:

ElenaW [278]2 years ago

3 0

3/6 cause there are 3 evens and 3 odds on a dice

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For what value of x is the parallelogram a rhombus.

Stells [14]

Answer:

Step-by-step explanation:

2 × ( 3x + 6 )° + ( 16x + 14 )° = 180°

22x + 26 = 180

22x = 154

x = 7

4 0

2 years ago

5. given ABC, find the value of x

Fudgin [204]

There's no question g

6 0

3 years ago

Factor the polynomial 8x² - 24x – 224 completely. A- 4(x + 4)(x-7) B- (4x + 16X(12x – 14) C- 8(x + 4)(x - 7) ht D- 2(4x + 16)(x

alisha [4.7K]

Answer:

The correct answer would be...

c. 8(x + 4)(x - 7)

Hope this helps!

8 0

3 years ago

The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

8 0

2 years ago

If three pounds of coffee costs $22.56, what is the cost of 1

NeX [460]

Answer:

$7.52 = 7 dollars and 52 cents.

Step-by-step explanation:

Given that three pounds of coffee = $22.56

1 pound of coffee = $22.56/3

Thus, we would have:

$\frac{22.56}{3} = 7.52$ .

A pound of coffee = $7.52

$7.52 = 7 dollars and 52 cents.

8 0

2 years ago