Ask question

Ask question

All categories

3 years ago

11

Sally's bake shop sells a box of brownies.Jonah divides the brownies amongst five friends.If each friend recieves 3 brownies,the

n how many brownies are in the box

1 answer:

Tasya [4]3 years ago

8 0

Answer:

15 brownies

Step-by-step explanation:

5 friends each have 3 brownies

you want to take 5 and multiply it by 3

5x3=15

15 brownies were in the box

You might be interested in

A gumball machine contains equal numbers of red, yellow, green, and blue gumballs. It randomly gives out one gumball for each pu

Oksi-84 [34.3K]

Answer: 50%

Step-by-step explanation: there are 4 options and it’s the probability of getting two

5 0

4 years ago

Suppose a random variable x is best described by a uniform probability distribution with range 22 to 55. Find the value of a tha

const2013 [10]

Answer:

(a) The value of <em>a</em> is 53.35.

(b) The value of <em>a</em> is 38.17.

(c) The value of <em>a</em> is 26.95.

(d) The value of <em>a</em> is 25.63.

(e) The value of <em>a</em> is 12.06.

Step-by-step explanation:

The probability density function of <em>X</em> is:

$f_{X}(x)=\frac{1}{55-22}=\frac{1}{33}$

Here, 22 < X < 55.

(a)

Compute the value of <em>a</em> as follows:

$P(X\leq a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.95\times 33=[x]^{a}_{22}\\\\31.35=a-22\\\\a=31.35+22\\\\a=53.35$

Thus, the value of <em>a</em> is 53.35.

(b)

Compute the value of <em>a</em> as follows:

$P(X< a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.49\times 33=[x]^{a}_{22}\\\\16.17=a-22\\\\a=16.17+22\\\\a=38.17$

Thus, the value of <em>a</em> is 38.17.

(c)

Compute the value of <em>a</em> as follows:

$P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.85=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.85\times 33=[x]^{55}_{a}\\\\28.05=55-a\\\\a=55-28.05\\\\a=26.95$

Thus, the value of <em>a</em> is 26.95.

(d)

Compute the value of <em>a</em> as follows:

$P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.89=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.89\times 33=[x]^{55}_{a}\\\\29.37=55-a\\\\a=55-29.37\\\\a=25.63$

Thus, the value of <em>a</em> is 25.63.

(e)

Compute the value of <em>a</em> as follows:

$P(1.83\leq X\leq a)=\int\limits^{a}_{1.83} {\frac{1}{33}} \, dx \\\\0.31=\frac{1}{33}\cdot \int\limits^{a}_{1.83} {1} \, dx \\\\0.31\times 33=[x]^{a}_{1.83}\\\\10.23=a-1.83\\\\a=10.23+1.83\\\\a=12.06$

Thus, the value of <em>a</em> is 12.06.

7 0

3 years ago

Help with this please!!

kompoz [17]

Answer:

Positive hope it help :D

Step-by-step explanation:

Sorry if I’m not right :/

6 0

2 years ago

Help with circle measurements asap plzzzz

antoniya [11.8K]

Answer:according to the formula of inscribed angle theorem

$3x + 22 = \frac{1}{2 } \times 134$

$3x + 22 = 67$

$3x = 67 - 22$

$3x = 45$

$x = \frac{45}{3}$

$x = 15$

The answer is 15 degrees

3 0

3 years ago

I need help this is due tomorrow !!!!! (start at the word jean)

madreJ [45]

A. Triangle...........................

3 0

3 years ago