9514 1404 393
Answer:
5 hours
Step-by-step explanation:
A quick way to look at this is to compare the difference in hourly charge to the difference in 0-hour charge.
The first day, the charge is $3 more than $12 per hour.
The second day, the charge is $12 less than $15 per hour.
The difference in 0-hour charges is 3 -(-12) = 15. The difference in per-hour charges is 15 -12 = 3. The ratio of these is ...
$15/($3/h) = 5 h
The charges are the same after 5 hours.
__
If you write equations for the charges, they will look like ...
y1 = 15 + 12(x -1)
y2 = 3 + 15(x -1)
Equating these charges, we have ...
15 +12(x -1) = 3 + 15(x -1)
12x +3 = 15x -12 . . . . . . . . eliminate parentheses
15 = 3x . . . . . . . . . . add 12-12x
x = 15/3 = 5 . . . . . . divide by 3
You might notice that the math here is very similar to that described in words, above.
The charges are the same after 5 hours.
The first set of expressions bc 3x is equivalent to 3x and -7y is equivalent to -7y
<span>X^2- 4x- 6y- 14=0
6y = x^2 - 4x - 14
Divide through by 6:-
y = (1/6)x^2 - (2/3)x - 7/3</span>
Answer:
u = -v + w + x
Step-by-step explanation:
Solve for u:
x = u + v - w
x = u + v - w is equivalent to u + v - w = x:
u + v - w = x
Subtract v - w from both sides:
Answer: u = -v + w + x
Answer:
8 and 10
Step-by-step explanation:
the ratio of the two numbers is 4:5
So let's take 4 and 5 as our number, we find out that their LCM is 20.
The next pair would be 8 and 10. Their LCM is 40 , so they are the numbers.