I'd start by listing out the multiplies of all three past 100, like this:
102, 104, 106, 108, 110, 112, 114, 116, 118, 120, 122, 124, 126, 128, 130
104, 108, 112, 116, 120, 124, 128, 132, 136
110, 120, 130, 140
Now it's just a matter of finding the number that is the same for all three of them, which is 120.
Mother would be WW and the father would be ww. So when you cross WW with ww, all the offsprings be heterozygous meaning they would all be Ww. So the possibility for the child to have a widows peak would be 100%
Its like that because your graphing it like A (1,2)B(2,5) Pretend your graphing something
Answer:
You first identify the variable.
Answer:
6/11
Step-by-step explanation:
2/11 x 3/11
