Ask question

Ask question

All categories

3 years ago

8

generate and solve another division problem with the same quotient and remainder as the two problems below. Explain your strateg

y for creating the new problem with a quotient of 3 and a remainder of 12

1 answer:

Zarrin [17]3 years ago

4 0

Answer:

The dividend is 51 and the divisor is 13.

Step-by-step explanation:

Since the remainder is 12, so the divisor must be greater than 12.

So, we can choose any number as a divisor which is greater than 12.

Assume the divisor is 13.

So, when we divide the dividend say, x by the divisor 13 then the quotient will be 3 and the remainder will be 12.

Therefore, x = 13 × 3 + 12 = 51

So, the dividend is 51 and the divisor is 13. (Answer)

You might be interested in

On a level field, a telephone pole 24 feet tall casts a shadow 6 feet long, and at the same time of day, another nearby telephon

nalin [4]

E. 72
6 feet long cast shadow = 24 feet pole
18 feet long cast shadow = 72 feet pole
18/6=3
24x3=72

5 0

3 years ago

Please answer I’ll rate brainlyest

12345 [234]

Answer:

$5P3*6C4=60*15=900$

Step-by-step explanation:

$5P3$ refers to the permutations of 5 items taken 3 at a time. To evaluate this, we use factorials as follows;

$5P3=\frac{5!}{(5-3)!}$

The factorial of an integer n is evaluated as;

$n!=n*(n-1)*(n-2)*(n-3).......3*2*1$

Using this concept, the above expression can now be simplified as follows;

$5P3=\frac{5!}{2!}=\frac{5*4*3*2!}{2!}=5*4*3=60$

Therefore, the permutations of 5 items taken 3 at a time is 60.

The next expression, $6C4$ refers to the combinations of 6 items taken 4 at a time. The simplification utilizes similar concepts of permutations since we shall be involving factorials;

$6C4=\frac{6!}{4!(6-4)!}=\frac{6!}{4!*2!}=\frac{6*5*4!}{4!*2*1}=\frac{6*5}{2*1}=15$

Therefore, the combinations of 6 items taken 4 at a time is 15.

The final step is to evaluate the product;

$5P3*6C4=60*15=900$

3 0

2 years ago

Which ordered pair makes both inequalities true? y < 3x – 1 y > –x + 4 On a coordinate plane, 2 straight lines are shown.

Katen [24]

Answer:

(4,0)

Step-by-step explanation:

we have

$y< 3x-1$ ----> inequality A

$y \geq -x+4$ ----> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)

Verify each ordered pair

case 1) (4,0)

<em>Inequality A</em>

$0< 3(4)-1$

$0< 11$ ----> is true

<em>Inequality B</em>

$0 \geq -(4)+4$

$0 \geq 0$ ----> is true

so

the ordered pair makes both inequalities true

case 2) (1,2)

<em>Inequality A</em>

$2< 3(1)-1$

$2< 2$ ----> is not true

so

the ordered pair not makes both inequalities true

case 3) (0,4)

<em>Inequality A</em>

$4< 3(0)-1$

$4< -1$ ----> is not true

so

the ordered pair not makes both inequalities true

case 4) (2,1)

<em>Inequality A</em>

$1< 3(2)-1$

$1< 5$ ----> is true

<em>Inequality B</em>

$1 \geq -(2)+4$

$1 \geq 2$ ----> is not true

so

the ordered pair not makes both inequalities true

5 0

2 years ago

Read 2 more answers

Box and whisker plots please help!

kotykmax [81]

The correct answer is D. 100%
Each tick counts as 8 so the beginning of the plot would be at 28 which is only 2 from 30 and everything else is on the plot is greater than 30 so the answer would have to be D since 75% would be too little coverage of the plot

5 0

2 years ago

Write an equation of the line that passes me that passes through (2,-5) and is parrallel to the line 2y=3x+10

Otrada [13]

Step-by-step explanation:

parallel means same slope/gradient

2y = 3x + 10

y = 1.5x + 5

let equation be y = 1.5x + b

sub (2, -5)

-5 = 1.5(2) + b

b = -8

therefore y = 1.5x - 8

Topic: Coordinate Geometry

If you like to venture further, feel free to check out my insta (learntionary). It would be best if you could give it a follow. I'll be constantly posting math tips and notes! Thanks!

7 0

2 years ago