(3 cos x-4 sin x)+(3sin x+4 cos x)=5
(3cos x+4cos x)+(-4sin x+3 sin x)=5
7 cos x-sin x=5
7cos x=5+sin x
(7 cos x)²=(5+sinx)²
49 cos²x=25+10 sinx+sin²x
49(1-sin²x)=25+10 sinx+sin²x
49-49sin²x=25+10sinx+sin²x
50 sin² x+10sinx-24=0
Sin x=[-10⁺₋√(100+4800)]/100=(-10⁺₋70)/100
We have two possible solutions:
sinx =(-10-70)/100=-0.8
x=sin⁻¹ (-0.8)=-53.13º (360º-53.13º=306.87)
sinx=(-10+70)/100=0.6
x=sin⁻¹ 0.6=36.87º
The solutions when 0≤x≤360º are: 36.87º and 306.87º.
Answer:
Using c++
Check the image for colors.
Step-by-step explanation:
#include <iostream>
using namespace std;
int main()
{
float length1,length2,width1,width2,area1,area2;
cout<<"length of Rectangle 1\n";
cin>>length1;
cout<<"\nwidth of Rectangle 1\n";
cin>>width1;
cout<<"\nlenght of Rectangle 2\n";
cin>>length2;
cout<<"\nwidth of Rectangle 2\n";
cin>>width2;
area1=length1*width1;
area2=length2*width2;
if (area1<area2)
{cout << "\nRectangle 2 has greater area";}
else {
if (area1>area2)
{cout << "\nRectangle 1 has greater area";}
else {cout << "\nAreas are the same";}
}
return 0;
}
Answer:
I don't know where those answers are coming from, but I got:
23s - 145