3 years ago

Model and partial quotient solve: 783/4

Mathematics

2 answers:

vlada-n [284]3 years ago

7 0

Answer:

195.75

Step-by-step explanation:

o-na [289]3 years ago

4 0

195.75 would be your answer, hope you have a good day :)

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Curium-243 has a half-life of 28.5 days. In a sample of 5.6 grams of curium-243, how many grams will remain after 12 days?

quester [9]

Answer:

C.4.18g

The amount will remain after 12 days is 4.18 g

Step-by-step explanation:

we can use formula

$P(t)=P_0(\frac{1}{2})^{\frac{t}{h} }$

where

h is half life time

t is time in days

Po is initial quantity

P(t) is the quantity after t days

we are given

Curium-243 has a half-life of 28.5 days

$h=28.5$

In a sample of 5.6 grams of curium-243

so,

$P_0=5.6$

now, we can plug values

$P(t)=5.6(\frac{1}{2})^{\frac{t}{28.5} }$

now, we can plug t=12

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The amount will remain after 12 days is 4.18 g

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4 years ago

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Answer:

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Jill wants to eat the same amount of pie every day so we need to divide the amount of pie by the amount of time. This gives us 4/10 which simplifies to 2/5. She should bring 2/5 a pie each day.

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