All categories

3 years ago

22. Evaluate -3x+x³ for x = -3

Mathematics

2 answers:

Rom4ik [11]3 years ago

6 0

Answer:

-18 is correct answer

Step-by-step explanation:

$-3x+x³ \\ - 3( - 3) + { ( - 3)}^{3} \\ + 9 - 27 \\ - 18$

hope it helped you:)

bekas [8.4K]3 years ago

3 0

Answer:

-18

Step-by-step explanation:

-3x + x³

-3(-3) + (-3)³

9 + (-27)

9 - 27 = -18

You might be interested in

Write the percent as a decimal 0.25%

Digiron [165]

Answer:

.0025

Step-by-step explanation:

.25%/100=.0025

7 0

3 years ago

Read 2 more answers

A math teacher instructed students to graph the following equations on a coordinate plane. y=2.5x+2 and y=2x+4. If graphed corre

algol [13]

Both the graphical lines will intersect at (4,12)

Step-by-step explanation:

Step 1; We must find the point in the graph where the lines of y=2.5x+2 and y=2x+4 intersect. To find out the intersecting point we must substitute values of x in both equations and see in which co-ordinate they are the same.

Step 2; We plot various values of x on the line governed by the equation y=2.5x+2

For a value of x=1 , y=2.5(1) + 2 = 4.5

For a value of x=2 , y=2.5(2) + 2 = 7

For a value of x= 3, y=2.5(3) + 2 = 9.5

For a value of x= 4, y=2.5(4) + 2 = 12

For a value of x= 5, y=2.5(5) + 2 = 14.5

Step 3; Now we also plot the values of x on the other line governed by y=2x+4

For a value of x= 1, y=2(1) + 4 = 6

For a value of x= 2, y=2(2) + 4 = 8

For a value of x= 3, y=2(3) + 4 = 10

For a value of x= 4, y=2(4) + 4 = 12

For a value of x= 5, y=2(5) + 4 = 14

Step 4; For both lines we must see if any of the values repeat at a particular point. In this case at the point (4,12) repeats for both so that becomes the point of intersection.

8 0

3 years ago

MATH :((<br>how do the chart??<br><img src="https://tex.z-dn.net/?f=%20-%20x%20%20%5E%7B2%7D%20%20-%209%20%5Cgeqslant%200" id="T

siniylev [52]

Answer:

<h2>no solution</h2>

Step-by-step explanation:

$-x^2-9\geq0\qquad\text{change the signs}\\\\x^2+9\leq0\\\\\text{the parabola}\ x^2\ \text{is op}\text{en up and shifted 9 units up. Therefore is whole}\\\text{over the x-axis (only positive values)}.\\\\\bold{CONCLUSION}:\\\\\bold{no\ solution}$