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3 years ago

22. Evaluate -3x+x³ for x = -3

Mathematics

2 answers:

Rom4ik [11]3 years ago

6 0

Answer:

-18 is correct answer

Step-by-step explanation:

$-3x+x³ \\ - 3( - 3) + { ( - 3)}^{3} \\ + 9 - 27 \\ - 18$

hope it helped you:)

bekas [8.4K]3 years ago

3 0

Answer:

-18

Step-by-step explanation:

-3x + x³

-3(-3) + (-3)³

9 + (-27)

9 - 27 = -18

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3tan x * cos x * cot x =

ruslelena [56]

Answer:

3cos(x)

Step-by-step explanation:

use cot(t) = 1/tan(t), transform the expression:

3tan(x)cos(x)x1/tan(x)

reduce the expression with tan(x):

3cos(x)

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3 years ago

Find the errors what equation do you get when you solve each equation for x

xxTIMURxx [149]

Answer:

Error in the third line.

Step-by-step explanation:

There is an error in the third line.

We are dividing through by 7 but mx is not divided by 7.

Correct solution is:

mx + 7nx =7

x(m + 7n) = 7

x = 7 / (m + 7n).

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3 years ago

There is 14 apple slice and there is 4 people how many should each get?

Lena [83]

3.5 each is what they should get.

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4 years ago

Read 2 more answers

if k is a half-plane determined by QR, then for every real number 0 < x < or = to 180, there is exactly one ray, QQP, that

zloy xaker [14]

Let me start from the meaning of half plane.you must have learned that there are two axes X and Y axes which includes positive X axes and negative X axes and there is positive Y axes and negative y axes. So there are four quadrants which i have explained in the figure. I have explained the meaning of Half plane in the Diagram also. Half plane=Figure obtained by covering any two adjacent regions of the coordinate axes.So we get four half planes.

Now your question is k is a half plane determined by QR, such that 0<x≤180 and there is exactly one ray QRP that lies in k

So, $0< \angle PQR \leq 180^\cir{0}$

8 0

3 years ago

Find a counterexample to show that the statement is false. Assume all sets are subsets of a universal set U = {1, 2, 3, 4, 5}. (

natka813 [3]

Answer:

For subsets A={1,2},B={2,3},C={1,2 5} of U = {1, 2, 3, 4, 5}.

A ∪ (B − C) = (A ∪ B) − (A ∪ C) does not hold.

Step-By-Step Explanation:

U = {1, 2, 3, 4, 5}.

A={1,2}

B={2,3}

C={1,2 5}

For the Left Hand Side

B-C={3}

A ∪ (B − C)= {1,2} ∪ {3} ={1,2,3}

Likewise, the Right Hand Side:

(A ∪ B)={1,2,3}

(A ∪ C)={1,2,5}

(A ∪ B)- (A ∪ C)= {1,2,3}-{1,2,5}={3}

Since, {1,2,3} ≠ {3}, A ∪ (B − C) = (A ∪ B) − (A ∪ C) does not hold.

7 0

3 years ago

22. Evaluate -3x+x³ for x = -3​

22. Evaluate -3x+x³ for x = -3