22. Evaluate -3x+x³ for x = -3

Part A Assume the ball passes through the points ( 3 , 8 ) , ( 5 , 20 3 ) , and ( 6 , 5 ) . Use this data to set up a system of

Zepler [3.9K]

The three system of equations are 9a + 3b + c = 8, 75a + 15b + 3c = 20, and 36a + 6b + c = 5.

<h3>What is a solution to a system of equations? (SOLUTION GRAPHICALLY)</h3>

For a solution to be the solution to a system, it must satisfy all the equations of that system, and like all points satisfying an equation are in their graphs, so solution to a system is the intersection of all its equation at a single point(as we need a common point, which is going to be the intersection of course)(this can be one or many, or sometimes none).

The general equation of parabola is given as,

y = ax² + bx + c

The first point is (3,8), therefore, we can write,

8 = a(3)² + b(3) + c

9a + 3b + c = 8

The second point is (5, 20/3), therefore, we can write,

20/3 = a(5)² + b(5) + c

75a + 15b + 3c = 20

The third point is (6, 5), therefore, we can write,

5 = a(6)² + b(6) + c

36a + 6b + c = 5

Hence, the three system of equations are 9a + 3b + c = 8, 75a + 15b + 3c = 20, and 36a + 6b + c = 5.

Learn more about System of equations:

brainly.com/question/26254258

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6 0

2 years ago

What is the y-intercept of the line that passes

lara [203]

The slope is

$\frac{-13-31}{1-(-10)}=-4$

So, the equation is

$y+13=-4(x-1)$

The y-intercept is when x=0, so

$y+13=-4(0-1) \\ \\ y+13=4 \\ \\ \boxed{y=-9}$

5 0

1 year ago

HELP, answer both questions please !!! I will mark as brainlest!!!

yawa3891 [41]

Answer:

D and B

Step-by-step explanation:

the angles subtract and the other starts and loops

8 0

2 years ago

Read 2 more answers

Can you please answer the question?

Roman55 [17]

The <em>trigonometric</em> expression $\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}$ is equivalent to the <em>trigonometric</em> expression $\sec \alpha \cdot \csc \alpha + 1$ .

<h3>How to prove a trigonometric equivalence</h3>

In this problem we must prove that <em>one</em> side of the equality is equal to the expression of the <em>other</em> side, requiring the use of <em>algebraic</em> and <em>trigonometric</em> properties. Now we proceed to present the corresponding procedure:

$\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}$

$\frac{\tan^{2}\alpha}{\tan \alpha - 1} + \frac{\frac{1}{\tan^{2}\alpha} }{\frac{1}{\tan \alpha} - 1 }$

$\frac{\tan^{2}\alpha}{\tan \alpha - 1} - \frac{\frac{1 }{\tan \alpha} }{\tan \alpha - 1}$

$\frac{\frac{\tan^{3}\alpha - 1}{\tan \alpha} }{\tan \alpha - 1}$

$\frac{\tan^{3}\alpha - 1}{\tan \alpha \cdot (\tan \alpha - 1)}$

$\frac{(\tan \alpha - 1)\cdot (\tan^{2} \alpha + \tan \alpha + 1)}{\tan \alpha\cdot (\tan \alpha - 1)}$

$\frac{\tan^{2}\alpha + \tan \alpha + 1}{\tan \alpha}$

$\tan \alpha + 1 + \cot \alpha$

$\frac{\sin \alpha}{\cos \alpha} + \frac{\cos \alpha}{\sin \alpha} + 1$

$\frac{\sin^{2}\alpha + \cos^{2}\alpha}{\cos \alpha \cdot \sin \alpha} + 1$

$\frac{1}{\cos \alpha \cdot \sin \alpha} + 1$

$\sec \alpha \cdot \csc \alpha + 1$

The <em>trigonometric</em> expression $\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}$ is equivalent to the <em>trigonometric</em> expression $\sec \alpha \cdot \csc \alpha + 1$ .

To learn more on trigonometric expressions: brainly.com/question/10083069

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6 0

2 years ago

At an appliance store, the price of a refrigerator is marked up 25% to $406.25.

OLga [1]

<span>304.688. Take 25% of 406.25, which is 101.562 and then subtract it from 406.25.</span>

5 0

3 years ago

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22. Evaluate -3x+x³ for x = -3​

22. Evaluate -3x+x³ for x = -3