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SVETLANKA909090 [29]
3 years ago
9

Write the word sentence as an inequality

Mathematics
1 answer:
Zarrin [17]3 years ago
4 0

Answer:

Step-by-step explanation:

n+2/3 ≥ 5 1/3

<h3>there is you answer! :)</h3>
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Write a coordinate proof given quadrilateral ABCD with vertices A (3, 2), B (8, 2), C (5, 0), and D (0, 0).
EleoNora [17]

Answer:

Step-by-step explanation:

There is really no way to show that of I know of without drawing it but here is this. I hope this helps and not really exact on position but that is very close.

4 0
3 years ago
Given: PRST is a square
xxTIMURxx [149]

Answer:

(1-\sqrt{2})a^2

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a

Thus,

MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a

Consider isosceles triangle MSC. In this triangle

MS=MC=(\sqrt{2}-1)a.

The area of this triangle is

A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}

Consider right triangle PTS. The area of this triangle is

A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2

5 0
3 years ago
Find the surface area of this prism.
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Can someone please help me with this?
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Find the lowest terms<br> fraction that's equal<br> to 0.71.
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71/100 is the lowest the fraction can get
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3 years ago
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