Question

If cosθ=40/41,find sinθ,cotθ,secθ

Answer 1

Hello. 

Angle Theta is equal to: x² + y² = r² OR $r = \sqrt{ x^{2} + y^{2} }$

40² + y² = 41²
1600 + y² = 1681
-1600        -1600
y² = 81
y = 9

x = 40, y = 9, r = 41

cos θ= $\frac{x}{r}$ = $\frac{40}{41}$

sin θ = $\frac{y}{r} = \frac{9}{41}$
cot θ = $\frac{x}{y} = \frac{40}{9}$
sec θ = $\frac{r}{x} = \frac{41}{40}$

Hopefully it makes sense! :)