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dem82 [27]
3 years ago
11

-2x + 4 = 14 show all work

Mathematics
1 answer:
umka21 [38]3 years ago
6 0

Answer:

x=-5

-2x + 4 = 14

      -4  = 14-4

       -2x=10

    -2/-2=10/-2=-5

          x=-5

Step-by-step explanation:

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Fred has 36 strawberries and 42 blueberries. He wants to use them to garnish desert so that each desert has the same number of b
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To do this problem you must find the GCF or the greatest common factor of 36 and 42. For example 36 can be made by 1 and 36 2 and 18 3 and 12 4 and 9 and 6 and 6. 42 can be made by 1 and 42 2 and 21 3 and 14 and 6 and 7. The highest common factor is 6. So, if you put 6 berries on all of the desserts, you will put 6 strawberries on 6 tarts and 6 blueberries on 7 tarts. That’s a total of 13 desserts
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Pls answer..<br>5 men earns Rs. 7500 in 3 days, gind the amount that earn by 3 men by 4 days, ​
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→ Find how much 1 man make in 3 days

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6 0
3 years ago
Y=-x^2+6x-4<br> Find the Axis of Symmetry and the Vertex, Also solve the whole equation.
Inessa [10]

Answer:

1. <em>Axis of symmetry</em>: x = 3

2. <em>Vertex:</em> (3,5)

3. <em>Solution of the equation</em>:

<u />

  • x-intercepts:

               (3-\sqrt{5},0) \\\\(3+\sqrt{5},0)

  • y-intercept: (0, -4)

Explanation:

<u>1. Equation:</u>

    y=-x^2+6x-4

<u>2. </u><em><u>Axis of symmetry:</u></em>

That is the equation of a parabola, whose standard form is:

                 y=ax^2+bx+c

Where:    

                 a=-1;b=6;c=-4

The axis of symmetry is the vertical line with equation:

               x=-b/2a

Substitute  a=-1,\text{ and }b=6

          x=-6/[(2)(-1)]=-6/(-2)=3

Thus, the axis of symmetry is:

            x=3

<em><u>3. Vertex</u></em>

<em><u /></em>

The x-coordinate of the vertex is equal to the axys of symmetry, i.e x = 3.

To find the y-xoordinate, substitute this value of x into the equation for y:

               y=-x^2+6x-4\\\\y=-(3)^2+6(3)-4=-9+18-4=5

Therefore, the vertex is (3, 5)

<u>4. Find the x-intercepts</u>

The x-intercepts are the roots of the equation, which are the points wher y = 0.

        y=-x^2+6x-4=0

Use the quadratic equation:

       x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} \\\\x=\frac{-6\pm\sqrt{(-6)^2-4(-1)(-4)} }{2(-1)}\\\\x_1=3-\sqrt{5} \\\\x_2=3+\sqrt{5}

<u>5. Find the y-intercept</u>

<u />

The y-intercet is the value of y when x=0:

         y=-x^2+6x-4\\\\y=-(0)^2+6(0)-4=-4

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grin007 [14]
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option C is the correct answer.
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3 years ago
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