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avanturin [10]
3 years ago
12

What is the median of a triangle?

Mathematics
2 answers:
ANEK [815]3 years ago
5 0
- - The median of a triangle is a line way (segment) meting in the middle of the triangle.

jeka943 years ago
4 0
The median of a triangle is a line segment joining a vertex to the midpoint of the opposing side. Since there are three sides of a triangle, there are exactly three medians, one from each vertex. They all intersect each other at the triangles centroid.
Hope this helps! :)
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30. Justify Reasoning The quotient of two negative integers results in an integer. How does the value of the quotient compare to
Ratling [72]
The quotient of 2 negative integers results in an integer.
-4/-2 = 2
the value of the quotient is positive whereas, the value of the original 2 integers are both negative. The reason being, is that when u divide two negatives, u get a positive.
6 0
3 years ago
What are the parallel sides of a trapezoid​
saul85 [17]

Answer:

Parallel means that the lines will never cross. If we look at a  traditional trapezoid, the top side and the bottom side are straight lines that will never cross one another. The left and right sides are slanted towards one another, to they are not parallel.

Hope this helped. : )

3 0
3 years ago
Simplify u^2+3u/u^2-9<br> A.u/u-3, =/ -3, and u=/3<br> B. u/u-3, u=/-3
VashaNatasha [74]
  The correct answer is:  Answer choice:  [A]:
__________________________________________________________
→  "\frac{u}{u-3} " ;  " { u \neq ± 3 } " ; 

          →  or, write as:  " u / (u − 3) " ;  {" u ≠ 3 "}  AND:  {" u ≠ -3 "} ; 
__________________________________________________________
Explanation:
__________________________________________________________
 We are asked to simplify:
  
  \frac{(u^2+3u)}{(u^2-9)} ;  


Note that the "numerator" —which is:  "(u² + 3u)" — can be factored into:
                                                      →  " u(u + 3) " ;

And that the "denominator" —which is:  "(u² − 9)" — can be factored into:
                                                      →   "(u − 3) (u + 3)" ;
___________________________________________________________
Let us rewrite as:
___________________________________________________________

→    \frac{u(u+3)}{(u-3)(u+3)}  ;

___________________________________________________________

→  We can simplify by "canceling out" BOTH the "(u + 3)" values; in BOTH the "numerator" AND the "denominator" ;  since:

" \frac{(u+3)}{(u+3)} = 1 "  ;

→  And we have:
_________________________________________________________

→  " \frac{u}{u-3} " ;   that is:  " u / (u − 3) " ;  { u\neq 3 } .
                                                                                and:  { u\neq-3 } .

→ which is:  "Answer choice:  [A] " .
_________________________________________________________

NOTE:  The "denominator" cannot equal "0" ; since one cannot "divide by "0" ; 

and if the denominator is "(u − 3)" ;  the denominator equals "0" when "u = -3" ;  as such:

"u\neq3" ; 

→ Note:  To solve:  "u + 3 = 0" ; 

 Subtract "3" from each side of the equation; 

                       →  " u + 3 − 3 = 0 − 3 " ; 

                       → u =  -3 (when the "denominator" equals "0") ; 
 
                       → As such:  " u \neq -3 " ; 

Furthermore, consider the initial (unsimplified) given expression:

→  \frac{(u^2+3u)}{(u^2-9)} ;  

Note:  The denominator is:  "(u²  − 9)" . 

The "denominator" cannot be "0" ; because one cannot "divide" by "0" ; 

As such, solve for values of "u" when the "denominator" equals "0" ; that is:
_______________________________________________________ 

→  " u² − 9 = 0 " ; 

 →  Add "9" to each side of the equation ; 

 →  u² − 9 + 9 = 0 + 9 ; 

 →  u² = 9 ; 

Take the square root of each side of the equation; 
 to isolate "u" on one side of the equation; & to solve for ALL VALUES of "u" ; 

→ √(u²) = √9 ; 

→ | u | = 3 ; 

→  " u = 3" ; AND;  "u = -3 " ; 

We already have:  "u = -3" (a value at which the "denominator equals "0") ; 

We now have "u = 3" ; as a value at which the "denominator equals "0"); 

→ As such: " u\neq 3" ; "u \neq -3 " ;  

or, write as:  " { u \neq ± 3 } " .

_________________________________________________________
6 0
3 years ago
In 2016, the top 1 percent of taxpayers accounted for more income taxes paid than the bottom 90 percent combined. The top 1 perc
qaws [65]

Answer:

$464Billion

Step-by-step explanation:

If 37.3%=$538B

32.2%=?

By \ Cross \ Multiplying:-\\32.2\%=>\frac{32.2\%*538}{40\%}\\=464.440

32.2% is roughly $464Billion in taxes

3 0
3 years ago
What is the value of x?​
masya89 [10]

Answer:

Option D is correct.

Step-by-step explanation:

We can tell that

  • 4x + \frac{x}{2} + 2 + \frac{3x-4}{2} = 180

Now, let's simplify.

=> 4x + 2 + \frac{4x-4}{2} = 180

=> 4x + 2 + 2x-2 = 180

=> 4x + 2x = 180

=> 6x = 180

=> x = 30

Therefore, Option D is correct.

Hoped this helped.

5 0
2 years ago
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