A 139-turn circular coil of radius 2.13 cm is immersed in a uniform magnetic field that is perpendicular to the plane of the coi
1 answer:
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a/b. The ball has velocity vector at time
where is the ball's initial speed and
.
c. At its highest point, the ball has 0 vertical speed. This occurs when
d. Recall that
so that at its highest point,
e. This is just twice the time it takes for the ball to reach its maximum height, .
f. The ball's horizontal position after time is
so that after the time found in part (f), the ball has traveled
Answer:
= 625 nm
Explanation:
We now that for
for maximum intensity(bright fringe) d sinθ=nλ n=0,1,2,....
d= distance between the slits, λ= wavelength of incident ray
for small θ, sinθ≈tanθ= y/D where y is the distance on screen and D is the distance b/w screen and slits.
Given
d=1.19 mm, y=4.97 cm, and, n=10, D=9.47 m
applying formula
λ= (d*y)/(D*n)
putting values we get
on solving we get
= 625 nm