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omeli [17]
3 years ago
9

My body is not just something that I have, my body is also I am

Physics
2 answers:
sertanlavr [38]3 years ago
8 0

Answer:

thats pretty cool k byeeeeeeee

Bond [772]3 years ago
4 0

Answer:

um ok

Explanation:

i guess

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A 1,200 kg dragster, starting from rest, reaches a maximum velocity of 140m/s in 5 seconds. At the 5 second mark, the dragster d
SSSSS [86.1K]

Answer:

Drag or air resistance

Explanation:

The force of friction caused by a moving fluid is called drag.  When that fluid is air, it's also known as air resistance.

8 0
3 years ago
A ball is thrown upward from the top of a building at an angle of 30.0° to the horizontal and with
Ray Of Light [21]

Answer:

See below

Explanation:

Vertical position = 45 +  20 sin (30) t  - 4.9 t^2

 when it hits ground this = 0

               0 = -4.9t^2 + 20 sin (30 ) t + 45

                0 = -4.9t^2 + 10 t +45 = 0     solve for t =4.22 sec

  max height is at  t= - b/2a = 10/9.8 =1.02

     use this value of 't' in the equation to calculate max height = 50.1 m

      it has  4.22 - 1.02 to free fall = 3.2 seconds free fall

           v = at = 9.81 * 3.2 = 31.39 m/s VERTICAL

      it will <u>also</u> still have horizontal velocity =  20 cos 30 = 17.32 m/s

        total velocity will be sqrt ( 31.39^2 + 17.32^2) = 35.85 m/s

Horizontal range = 20 cos 30  * t  =  20 *  cos 30  * 4.22 = 73.1 m

8 0
1 year ago
A projectile is launched straight upwards at 75 m/s. Three seconds later, its velocity is...?
yawa3891 [41]

Answer:

V = V0 + a t

V = 75 - 9.8 * 3 = 45.6 m/s

4 0
2 years ago
A water line enters a house 2.0 m below ground. A smaller diameter pipe carries water to a faucet 5.0 m above ground, on the sec
nirvana33 [79]

Answer:

 P₁- P₂ = 91.1 10³ Pa

Explanation:

For this exercise we will use Bernoulli's equation, where point 1 is at the bottom of the house and point 2 on the second floor

          P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

          P1-P2 = ½ ρ (v₂² - v₁²) + ρ g (y₂-y₁)

In the exercise they give us the speeds and the height of the turbid, so we can calculate the pressure difference

For heights let's set a reference system on the ground floor of the house, so we have 5m for the second floor and an entrance at -2m

 

        P₁-P₂ = ½ 1.0 10³ (7² - 2²) + 1.0 10³ 9.8 (5 + 2)

       P₁-P₂ = 22.5 10³ + 68.6 10³

       P₁- P₂ = 91.1 10³ Pa

3 0
3 years ago
PLEASE HELP!!! GIVING BRAINLIEST!! ill also answer questions that you have posted if you answer this correctly!!!! (40pts)
Soloha48 [4]

Answer:

Newton's second law: F=ma.

Force = mass x acceleration

This basically means, that the more massive something is, and the faster it is going, the more force the object will have.

So, the factors that can be used to find acceleration are:

F=ma

a=F/m

So, we see that the correct answer is A, mass and force.

Let me know if this helps!

8 0
2 years ago
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