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bagirrra123 [75]
3 years ago
13

You perform a double‑slit experiment in order to measure the wavelength of the new laser that you received for your birthday. Yo

u set your slit spacing at 1.03 mm and place your screen 8.49 m from the slits. Then, you illuminate the slits with your new toy and find on the screen that the tenth bright fringe is 4.69 cm away from the central bright fringe (counted as the zeroth bright fringe). What is your laser's wavelength expressed in nanometers?
Physics
1 answer:
BigorU [14]3 years ago
8 0

Answer:

\lambda = 6.25\times10^{-9}= 625 nm

Explanation:

We now that for

for maximum intensity(bright fringe) d sinθ=nλ n=0,1,2,....

d= distance between the slits, λ= wavelength of incident ray

for small θ, sinθ≈tanθ= y/D where y is the distance on screen and D is the distance b/w screen and slits.

Given

d=1.19 mm, y=4.97 cm,  and,   n=10,   D=9.47 m

applying formula

λ= (d*y)/(D*n)

putting values we get

\lambda = \frac{1.19\times10^{-3}\times4.97\times10^{-2}}{9.47\times10}

on solving we get

\lambda = 6.25\times10^{-9}= 625 nm

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Recall the definitions of

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Take the initial position to be the origin, so x[initial] = 0, and we simply write x[final] = s. So

v[ave] = s/t

• average acceleration:

a[ave] = ∆v/∆t = (v[final] - v[initial])/t

Assume acceleration is constant (a[ave] = a). Let v[initial] = u and v[final] = v, so that

a = (v - u)/t

Under constant acceleration, the average velocity is also given by

v[ave] = (v[final] + v[initial])/2 = (v + u)/2

Then

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and

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s = ((u + at) + u) t/2

s = (2u + at) t/2

s = ut + 1/2 at²

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2 years ago
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Answer:

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