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2 years ago

Write 1,386 as the product of its prime factors. A. 2 x 3 x 3 x 7 x 11 B. 2 x 693 C. 2 x 3 x 7 x 33 D. 2 x 3 x 231

1 answer:

5 0

Hello there,

The "prime factor's" of 1,386 would be "2*3*3*7*11.

When we multiply those together. We get 1,386.

Hope this helps.

~Jurgen

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3 years ago

A and b are positive integers. Find <img src="https://tex.z-dn.net/?f=-2a%2B3b" id="TexFormula1" title="-2a+3b" alt="-2a+3b" ali

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A could be 2 while B could be 3, so -2a+3b turns into -4+9, which equals 5.

From what I know you can't really solve a a single equation with two-variables so it's just a matter of trial and error.

Just try plugging in a small number like 2 for a just to try it and you get 8b^2=72.

Divide everything by 8 to isolate b and you get that b^2=9.

Square root everything and you'll find that b=3. This is just one possible combination, I'm sure there are many more but this is obviously the one that was intended to be found.

Now that we know that a=2 and b=3 just plug them into the equation.

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Sorry about having to use this ^ symbol, the equation maker is not working.

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