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Illusion [34]
3 years ago
11

Can anyone help me out

Mathematics
1 answer:
Genrish500 [490]3 years ago
5 0

Answer:

12k^5 +24k⁴+30k³

Step-by-step explanation:

the area = 6k³(2k²+4k+5)

= 12k^5 +24k⁴+30k³

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Find the area of the composite figure.
Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

<u>According to the Figure Given:</u>

Total Horizontal Distance = 14 in

Length = 6 in

<u>To Find :</u>

The Area of the composite figure

<u>Solution:</u>

Firstly we need to find the area of Rectangular part.

So We know that,

\boxed{ \rm \: Area  \:  of \:  Rectangle = Length×Breadth}

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

\boxed{\rm \: Breadth = total  \: distance - Radius}

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

\longrightarrow\rm \: Length \:  of \:  the  \: circle = Radius

  • Since Length = 6 in ;

\longrightarrow \rm \: 6 \: in   = radius

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

  • Total Horizontal Distance= 14
  • Radius = 6

\longrightarrow\rm \: Breadth = 14-6

\longrightarrow\rm \: Breadth = 8 \: in

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

  • Length = 6
  • Breadth = 8

\longrightarrow\rm \: Area \:  of  \: Rectangle = 6 \times 8

\longrightarrow \rm \: Area \:  of  \: Rectangle = 48 \: in {}^{2}

Then, We need to find the area of Quarter circle :

We know that,

\boxed{\rm Area_{(Quarter \; Circle) }  = \cfrac{\pi{r} {}^{2} }{4}}

Now Substitute their values:

  • r = radius = 6
  • π = 3.14

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 6 {}^{2} }{4}

Solve it.

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 36}{4}

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}

\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9

\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \:  {in}^{2}

Now we can Find out the total Area of composite figure:

We know that,

\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}

So Substitute their values:

  • \rm Area_{(rectangle)} = 48
  • \rm Area_{(Quarter Circle)} = 28.26

\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26

Solve it.

\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

\rule{225pt}{2pt}

I hope this helps!

3 0
2 years ago
if it takes 10 men 10 days to dig a hole how long will it take 5 men to dig a hole that's half as big
Nataly [62]

Answer:

10 days

Step-by-step explanation:

It will take 10 men 5 days to dig a hole half as big.

It will take 5 men 10 days to dig a hole half as big.

( Remember, the less people, the more time it will take. )

8 0
2 years ago
Read 2 more answers
Find the surface area. *<br> 2)<br> 14 km<br> 11 km<br> 6.3 km<br> 7 km<br> 5 km
ella [17]

Answer:

pp

Step-by-step explanation:

6 0
3 years ago
A certain building has a triangular shaped face to link up of the sides of the triangular base or 145 feet 257 feet in 290 feet
attashe74 [19]

Answer:

18617.66 ft^2

Step-by-step explanation:

sides of triangular base

a=  145ft  ,

b = 257ft ,

c =  290ft

<u>calculate the area of the base  </u>

The base is a scalene triangle hence the area is calculated as follows

s = ( a + b + c ) / 2

  = ( 145 + 257 + 290 ) / 2 = 346

Area of triangle = \sqrt{s(s-a)(s-b)(s-c)}  = \sqrt{346(201)(89)(56)}

                          = 18617.66 ft^2

3 0
2 years ago
If 3 Onions Weigh 0.75lb how much do 10 onions weigh
fomenos
First find out how much one onion weighs so divide 0.75 by 3. This gets you 0.25. Now all you need to do is multiply the weight of one onion by 10, 0.25 x 10 = 2.5
3 0
3 years ago
Read 2 more answers
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