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4 years ago

PLEAASSEEE HELP ASAP!!!

Mathematics

2 answers:

eduard4 years ago

8 0

Answer:

$= 2 \frac{7}{23} \\ \\$

Step-by-step explanation:

$5 \frac{3}{8} - 3 \frac{1}{6} \\ \\ \frac{43}{8} - \frac{19}{6} \\ \\ \frac{258 - 152}{48} \\ \\ \frac{106}{48} \\ \\ \frac{53}{23} = \: \: 2 \frac{7}{23}$

mars1129 [50]4 years ago

4 0

Answer:

$2\frac{5}{24}$

Step-by-step explanation:

First, the denominator needs to be the same. The smallest number that both numbers have in common is 24.

Since, the denominator of both is 24, the fractions won't be same because the numerator is the same.

For 3/8, we get 24 by multiplying 8 times 3. So, to make the fraction equal to the original, we have to multiply 3 by 3 (numerator) as well: $\frac{9}{24}$

Same for 1/6, we get 24 by multiplying 6 times 4. So, to make the fraction equal to the original, we have to multiply 4 by 1 (numerator) as well: $\frac{4}{24}$

Then, to find the FINAL fraction, we have to subtract the numerator only.

$\frac{9}{24}-\frac{4}{24}=\frac{5}{24}$

For the WHOLE number,s you just subtract those like normal. 5 - 3 = 2

Final answer under "answer" heading

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We learned in that about 69.7% of 18-20 year olds consumed alcoholic beverages in 2008. We now consider a random sample of fifty

maw [93]

Answer:

(1) The expected number of people who would have consumed alcoholic beverages is 34.9.

(2) The standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3) It is surprising that there were 45 or more people who have consumed alcoholic beverages.

Step-by-step explanation:

Let X = number of adults between 18 to 20 years consumed alcoholic beverages in 2008.

The probability of the random variable X is, p = 0.697.

A random sample of n = 50 adults in the age group 18 - 20 years is selected.

An adult, in the age group 18 - 20 years, consuming alcohol is independent of the others.

The random variable X follows a Binomial distribution with parameters n = 50 and p = 0.697.

The probability mass function of a Binomial random variable X is:

$P(X=x)={50\choose x}0.697^{x}(1-0.697)^{50-x};\ x=0,1,2,3...$

(1)

Compute the expected value of X as follows:

$E(X)=np\\=50\times 0.697\\=34.85\\\approx34.9$

Thus, the expected number of people who would have consumed alcoholic beverages is 34.9.

(2)

Compute the standard deviation of X as follows:

$SD(X)=\sqrt{np(1-p)}=\sqrt{50\times 0.697\times (1-0.697)}=10.55955\approx10.56$

Thus, the standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3)

Compute the probability of X ≥ 45 as follows:

P (X ≥ 45) = P (X = 45) + P (X = 46) + ... + P (X = 50)

$=\sum\limits^{50}_{x=45} {50\choose x}0.697^{x}(1-0.697)^{50-x}\\=0.0005+0.0001+0.00002+0.000003+0+0\\=0.000623\\\approx0.0006$

The probability that 45 or more have consumed alcoholic beverages is 0.0006.

An unusual or surprising event is an event that has a very low probability of success, i.e. p < 0.05.

The probability of 45 or more have consumed alcoholic beverages is 0.0006. This probability value is very small.

Thus, it is surprising that there were 45 or more people who have consumed alcoholic beverages.

6 0

3 years ago

Find the magnitude of wx for w(6 -3 6) and x(6 3 4) A. 2sqrt10 B. 35 C. 4sqrt2 D. 32

gladu [14]

Answer:

$|WX|=2\sqrt{10}$

Step-by-step explanation:

To find the distance between two points in there dimensional coordinate system, we use the formula;

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$

The magnitude for w(6 ,-3 , 6) and x(6, 3, 4)

$|WX|=\sqrt{(6-6)^2+(3--3)^2+(4-6)^2}$

$|WX|=\sqrt{(0)^2+(6)^2+(-2)^2}$

$|WX|=\sqrt{0+36+4}$

$|WX|=\sqrt{40}$

$|WX|=2\sqrt{10}$

The correct choice is A.

4 0

3 years ago

Find sin 22 1/2 ° please help

Georgia [21]

Answer:

0.69465837 is the answer

7 0

3 years ago

Find the 44th percentile, P44, from the following data! pls help

irina [24]

Answer:

$P_{44} = 29.9$

Step-by-step Explanation:

The 44th percentile, $P_{44}$ , of the given data can be calculated using the kth formula for percentile given as:

$i = \frac{k}{100}(n + 1)$

where,

i = the ranking or the position of the percentile = ?

k = the percentile = 44

n = total number of the given data values = 23

Plug in the values into the formula to find "i"

$i = \frac{44}{100}(23 + 1)$

$i = \frac{44}{100}(24)$

$i = \frac{1,056}{100}$

$i = 10.56$

Since "I", 10.56, is not an integer, round the number down, and round it up to the nearest integer, then look for the position each occupy in the ordered data set, and find their average.

Thus,

$i_{down} = 10.56 = 10$

$i_{up} = 10.56 = 11$

The data occupying the 10th position on the data set = 28.7

11th = 31.1

$P_{44} = \frac{28.7 + 31.1}{2} = \frac{59.8}{2}$

$P_{44} = 29.9$

6 0

3 years ago

Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x. (5 points)

Salsk061 [2.6K]

F(x)=(x-8)/(x+7). g(x)=(-7x-8)/(x-1). Plug in g(x) into f(x), f(g(x))=[(-7x-8)/(x-1)-8]/[-7x-8)/(x-1)+7], which can be simplified as (-7x-8-8x+8)/(-7x-8+7x-7)=-15x/-15=x. Plug in f(x) into g(x), g(f(x))=[-7*(x-8)/(x+7)-8]/[(x-8)/(x+7)-1]=(-7x+56-8x-56)/(x-8-x-7)=-15x/-15=x, as desired.

8 0

3 years ago

PLEAASSEEE HELP ASAP!!!​

PLEAASSEEE HELP ASAP!!!