The molecular formula<span> add the structure to a </span>empirical formula<span>. A </span>molecular formula<span> is identical to the </span>empirical formula<span>, and is based on quantity of atoms of each type in the </span>compound<span>.</span>
<span>Molarity is expressed as
the number of moles of solute per volume of the solution. We calculate as follows:
2.80 g ( 1 mol / 56.11 g ) = 0.05 mol KOH
Molarity = 0.05 mol KOH / 750 mL ( 1 L / 1000 mL )
Molarity = 0.07 M
Hope this answers the question. Have a nice day.</span>
Answer:
![M_{base}=6M](https://tex.z-dn.net/?f=M_%7Bbase%7D%3D6M)
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to realize this is a question about titration, which base solved by knowing that the HCl reacts with the NaOH in a 1:1 mole ratio, and therefore, we can write the following:
![M_{acid}V_{acid}=M_{base}V_{base}](https://tex.z-dn.net/?f=M_%7Bacid%7DV_%7Bacid%7D%3DM_%7Bbase%7DV_%7Bbase%7D)
Thus, we solve for the molarity of the base, NaOH, as shown below:
![M_{base}=\frac{M_{acid}V_{acid}}{V_{base}} \\\\M_{base}=\frac{3L*2M}{1.00L}\\\\M_{base}=6M](https://tex.z-dn.net/?f=M_%7Bbase%7D%3D%5Cfrac%7BM_%7Bacid%7DV_%7Bacid%7D%7D%7BV_%7Bbase%7D%7D%20%5C%5C%5C%5CM_%7Bbase%7D%3D%5Cfrac%7B3L%2A2M%7D%7B1.00L%7D%5C%5C%5C%5CM_%7Bbase%7D%3D6M)
Regards!
<span>2, 4 its the answer hope it helps</span>
Answer:
N₂ + 3H₂ → 2NH₃ ΔH = - 92.2KJ
Explanation:
Let's write out the chemical equation between Nitrogen and Hydrogen to Form Ammonia.
Nitrogen + Hydrogen = Ammonia
N₂ + H₂ → NH₃
A Thermochemical Equation is a balanced stoichiometric chemical equation that includes the enthalpy change, ΔH.
The balanced stoichiometric chemical equation is given as;
N₂ + 3H₂ → 2NH₃
92.2 kJ of energy are evolved for each mole of N2(g) that reacts. And from the equation, 1 mole of N2 reacts.
The enthalpy change, ΔH = - 92.2KJ. The negative sign is because heat is being evolved.
The balanced thermochemical equation;
N₂ + 3H₂ → 2NH₃ ΔH = - 92.2KJ