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erastova [34]
3 years ago
11

Match the statements with the atmospheric layer they describe.

Chemistry
2 answers:
vekshin13 years ago
6 0

The correct matches are:

1. Exosphere - Temperatures reach as high as 2000 C yet it feels very cold

This is the top layer of the atmosphere. The atoms are so dispersed that despite it having very high temperature it doesn't feel like it at all.

2. Thermosphere - Particles that have enough energy can escape into space

The thermosphere is the fourth highest layer of the atmosphere. The atoms in this layer are relatively distant from one another, so the particles that have enough energy manage to escape easily into the exosphere and then the space.

3. Mesosphere - It is the coldest region of the atmosphere

The mesosphere is the third highest layer. In this layer the temperatures constantly drop, and they go down to -85 degrees, making it the coldest layer by far.

4. Stratosphere - Ninety percent ozone is in this layer

The startosphere has a separte zone in it which is dominated by only one gas, the ozone. It is called the ozone layer, the one that protects the Earth from too intense UV radiation, and in fact over 90% of this gas is locate here.

5. Troposphere - It is warm due to the heat from Earth's surface

The troposphere is the densest and lowest of the layers. It is the one that also has Greenhouse gases which manage to trap the heat that is radiated from the surface of the Earth, thus keeping this layer relatively warm.

ella [17]3 years ago
4 0

1. Exosphere - Particles that have enough energy can  escape into space.

2. Thermosphere - Temperatures reach as high as 2000°C,  yet it feels very cold.

3. Mesosphere - It is the coldest region of the atmosphere

4. Stratosphere - Ninety percent of ozone is in this region

5. Troposphere - t is warm due to the heat from  Earth’s surface.

I've taken the Plato test and these are the correct answers. :-)

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Answer:

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Explanation:

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During an endothermic phase change, what happens to the potential energy and the kinetic energy?
Dovator [93]
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3 years ago
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¿Qué tipo de Inter conversión existe en una celda galvánica o en una celda electrolítica? a) de energía química a energía eléctr
insens350 [35]

Answer:

Opción a)

Explanation:

En este caso, vamos a explicartelo descartando opciones. Para empezar el proceso que existe en una celda galvánica o electrolítica, es lo que uno llama un proceso de Electroquímica, y permite manipular y usar la energía electrica para generar una reacción.

En este caso, yo tengo por ejemplo una celda galvánica con dos componentes como hierro y cobre conectados mediante una celda. El proceso de reacción entre ellos es lo que ayudará a que se genere energia electrica y esto, encendería un bombillo de luz. También puede ocurrir lo contrario. Con electricidad, se genera una reacción química. En estos casos, se genera una reacción de tipo REDOX (Oxido reducción).

Tomando en cuenta esto, la respuesta correcta sería la opción a). Veamos por que las otras opciones no son:

b) Energía eléctrica a química

Esta opción es falsa, porque estaría supeditando que una reacción solo puede darse por medio de una manipulación de la energía electrica y en las celdas galvánicas no ocurre eso, sino al revés.

c) Energía química a eléctrica

Falsa, porque es igual que la anterior, solo está supeditado a que ocurra este tipo de reacciones y no es así.

d) energía lumínica a eléctrica

Falso porque la energía lumínica proviene tambien de la electricidad, y en el caso de una celda galvánica se genera una reacción por lo que existe otro tipo de energía.

Espero esto te ayude.

7 0
3 years ago
5. A beam of photons with a minimum energy of 222 kJ/mol can eject electrons from a potassium surface. Estimate the range of wav
torisob [31]

Answer: The range of wavelengths of light that can be used to cause given phenomenon is 8.953 \times 10^{21} m.

Explanation:

Given: 222 kJ/mol (1 kJ = 1000 J) = 222000 J

Formula used is as follows.

E = \frac{hc}{\lambda}

where,

E = energy

h = Planck's constant = 6.625 \times 10^{-25} Js

c = speed of light = 3 \times 10^{8} m/s

Substitute the values into above formula as follows.

E = \frac{hc}{\lambda}\\222000 J = \frac{6.625  \times 10^{-34}Js \times 3 \times 10^{8} m/s}{\lambda}\\\lambda = 8.953 \times 10^{21} m

Thus, we can conclude that the range of wavelengths of light that can be used to cause given phenomenon is 8.953 \times 10^{21} m.

7 0
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#6- Accept or reject your hypothesis
#7- Record results
Hope this helps.
3 0
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