The answer to this question would be the last choice (this data has no outliers)
Explanation: The reason for this is that an outlier is basically any number or value that kind of stands off or is very separated from a set of data.
For example, if I had the numbers 1,2,3,2,9,5,7,5,8,4 and 47, 47 would definitely be an outlier as it's significantly greater than the rest of the data.
The data shown in your question doesn't vary a lot though, (it's contained within a range of 65 and 80- no number seems to be radically different).
A = 900
The area of a parallelogram can be found by taking its base (b) and multiplying by the height (h). The base has the measure of 33 +12 = 45 cm. Now, you just need to find the height of the parallelogram. The height can be found by using the pythagorean theorem (
.
So, when simplified the height of the parallelogram will be found from
The height is 20 cm. The base is 45 cm. 45 x 20 = 900.
Answer:
Step-by-step explanation:
AB = 
= 
Yep... so they says that the area of the extended leaf is 18+6x... You know that the area is length into breath... here the breath doesn't change.. so it'll be 3ft... can get the length by dividing area by 3... that is 6+2x... Now the new length wil be 2times that plus the previous 6ft length
Answer:
y=3/2x+0
Step-by-step explanation:
The formula for slope intercept form formula is y=mx+b where m is the slope and b is the y intercept and since the slope is rise over run ( or rise/run just put it into fraction form) we count from the y intercept up until we can see the line reach a point where it touches a actual cross point ( in this case from the y intercept we see it goes up three) Then we count over how many to that cross point ( the full point, not just a random place on the chart) (in this case 2) and that creates 3/2. Now for the y intercept. Where does the line intercept the vertical line? That's your y intercept. In this case it's 0. Now you can see where we count up from three ( for the slope) and over two. Right onto that point. Hope this makes sense! If not look up Khan academy for some extra tutoring that is free.
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