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2 years ago

Find the midpoint of the segment that has endpoints at (a+b, a-b) and (a, b).

Mathematics

1 answer:

Hunter-Best [27]2 years ago

5 0

Answer:

((2a+b)/2 , a/2)

Step-by-step explanation:

The midpoint is the mean/average of both the x and y values.

Our x values are a+b and a

Our y values are a-b and b

The midpoint x value is (a+b + a ) /2 = (2a + b)/2

The midpoint y value is (a-b + b) /2 = (a)/2

The midpoint combines these two values to get ((2a+b)/2 , a/2) as our midpoint

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Klio2033 [76]

It’s 50/50 hope this helps

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2 years ago

Read 2 more answers

The graph of which function(s) will contain the point (4, 12)? y = x + 8 y = 3x y = 2x y = x + 6

Alex777 [14]

Answer:

y=x+8 and y=3x

Step-by-step explanation:

The Given point is (4,12)

now we can substitute the point in each of the function and check wether it lies on it or not.

A. y=x+8

substitute y=12,x=4

12=4+8=12 which is true

B. y=3x

substitute y=12,x=4

12=3*4=12 which is true

C. y=2x

substitute y=12,x=4

12=2*4=8 which is not true

D. y=x+6

substitute y=12,x=4

12=4+6=10 . which is not true

Therefore option A and B are correct.

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3 years ago

2x – 4y = 16<br> -2x - 3y = 7

noname [10]

Bro use the app Socratic

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2 years ago

Sound travels through air at about 13 of a kilometer per second. If thunder is heard 6 seconds after a flash of lightning, about

Margarita [4]

If sound travels through air at around 13 of a kilometer per second, and thunder is heard 6 seconds after a flash of lightning, it would be 78ths of a kilometer. Although, I can't simplify that for you. Sorry. ^-^

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2 years ago

A 20 foot ladder is resting against the side of the house the base of the latter is 4 feet away from the house approximately how

notka56 [123]

The ladder resting against the house forms a triangle similar to the one in the image below

To answer this question you must use Pythagorean theorem

$a^{2} +b^{2}=c^{2}$

a and b are the legs (the sides that form a perpendicular/right angle)

c is the hypotenuse (the side opposite the right angle)

In this case...

a = x

b = 4

c = 20

^^^Plug these numbers into the theorem

$x^{2} +4^{2} =20^{2}$

solve for x

$x^{2}$ + 16 = 400

$x^{2}$ = 384

x = 8√6

x ≈ 19.5959....

Hope this helped!

~Just a girl in love with Shawn Mendes

5 0

3 years ago