Answer:

Step-by-step explanation:
<u>Arithmetic Sequences</u>
The arithmetic sequences are identified because any term n is obtained by adding or subtracting a fixed number to the previous term. That number is called the common difference.
The equation to calculate the nth term of an arithmetic sequence is:

Where
an = nth term
a1 = first term
r = common difference
n = number of the term
We are given the first terms of a sequence:
-12, -28, -44,...
Find the common difference by subtracting consecutive terms:
r = -28 - (-12) = -16
r = -44 - (-28) = -16
The first term is a1 = -12. Now we calculate the term n=61:



Answer:
133.33 years
Step-by-step explanation:
Given that:
Principal = $500
Interest rate (r) = 1.5% = 0.015
Triple amount of principal = $500 * 3 = $1500 = final amount (A)
Number of years (t) =?
Using the relation :
A = P(1 + rt)
1500 = 500(1 + 0.015t)
1500 / 500 = 1 + 0.015t
3 = 1 + 0.015t
3 - 1= 0.015t
2 = 0.015t
2 / 0.015 = 0.015t / 0.015
133.333 = t
133.33 years
Answer:
Distance=13.60
Step-by-step explanation:
The Distance between the two points in coordinate system is find by using the distance formula.
If two points
and
are given:

For the points:


The distance between the points is 13.60
Answer:
Option C.
Step-by-step explanation:
Total population = 1000 snails
AA = 160 snails
Aa = 480 snails
aa = 360 snails
Frequency of each type.



Now, we get

he frequency of the A allele in this population is 0.4.
Therefore, the correct option is C.
9514 1404 393
Answer:
1 < 15 -2a < 7
Step-by-step explanation:
There are a couple of ways you can do this.
1) Put the minimum and maximum values of a into the expression to see what its corresponding values are:
15-2a for a=4:
15-2(4) = 7
15-2a for a=7:
15-2(7) = 1
Then ...
1 < 15-2a < 7
__
2) Solve for a in terms of the value of 15-2a, then impose the limits on a.
x = 15 -2a
2a = 15 -x
a = (15 -x)/2
Now, impose the given limits:
4 < (15 -x)/2 < 7
8 < 15 -x < 14 . . . multiply by 2
-7 < -x < -1 . . . . . . subtract 15
7 > x > 1 . . . . . . . . multiply by -1
1 < 15-2a < 7 . . . . . use x=15-2a
_____
The vertical extent of the attached graph is the range of possible values of 15-2a. It goes from 1 to 7.