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2 years ago

1)a-19=3 2) y/7=10 3)5g=100 solve please

1 answer:

6 0

Are these three different questions? if so:
1: add 19 to both sides to get a = 3 +19
answer: a = 22

2: multiply both sides by 7 to get y = 10 * 7
answer: y = 70

3: divide both sides by 5 to get g = 100/5
answer: g = 20

hope this helped! good luck :)

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Answer:

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Step-by-step explanation:

*The nearest tenth of a foot is 347.2 ft.

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2 years ago

Help me on #13 and please explain

hichkok12 [17]

Answer:

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Step-by-step explanation:

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3 years ago

What’s the volume of a rectangle solid with the given dimensions: length 20, width 23, height 26

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The volume of the rectangular solid is: 11,960 units³.

<h3>How to Find the Volume of a Rectangular Solid?</h3>

The formula to find the volume of a rectangular solid is: (length)(width)(height).

Given the dimensions as:

Length = 20 units
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Height = 26 units

Volume = (20)(23)(26)

Volume of the rectangular solid = 11,960 units³.

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brainly.com/question/15116803

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1 year ago

A red gumball is 2 5/8 Inches across. A green gumball is 2 5/6 inches across and a blue gumball in 2 7/9 inches across. list the

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3 years ago

For a fair coin, suppose you toss the coin 100 times.

Natasha_Volkova [10]

Using the normal distribution, it is found that there is a 0.0005 = 0.05% probability of getting more than 66 heads.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with $\mu = np, \sigma = \sqrt{np(1-p)}$ .

For the binomial distribution, the parameters are given as follows:

n = 100, p = 0.5.

Hence the mean and the standard deviation of the approximation are given as follows:

$\mu = np = 100(0.5) = 50$ .

$\sigma = \sqrt{np(1-p)} = \sqrt{100(0.5)(0.5)} = 5$

Using continuity correction, the probability of getting more than 66 heads is P(X > 66 + 0.5) = P(X > 66.5), which is <u>one subtracted by the p-value of Z when X = 66.5</u>.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{66.5 - 50}{5}$

Z = 3.3

Z = 3.3 has a p-value of 0.9995.

1 - 0.9995 = 0.0005.

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1 year ago