The answer is C. Hope this helps :)
So we know that the Bruno's BAkery uses 4/9 barrels and that Cosmo's Bakery uses 6/5 as much. So we have to multiply 4/9 * 6/5 which is equal to 0.53 for one day.
Since they are asking for the 3/7 of the week we multiply 3/7 *0.53.
This is equal to 0.23 or 23/100
:3
Answer:
see below
Step-by-step explanation:
find common denominator and add the fractions in numerator and denominator:
1/x² + 2/y = y+2x²/x²y
5/x -6/y² =5y² -6x/xy²
(y+2x²)/x²y / (5y²-6x)/xy² change into multiplication
(y+2x²)/x²y * xy²/(5y²-6x)
simplify
y(y+2x²)/ x(5y²-6x)
There is not enough information to calculate this.
<span>Knowing the weight ratio of the fox to coyote as 3:8 in no way allows you to know the respective ratio of the wolf. To know the weight of the wolf would require knowing its ratio value, then the weights of all 3 is an easy calculation. </span>
<span>Example - 3:8:15 (f:c:w) is a plausible ratio based upon real-world weight averages for certain species/subspecies of the three. </span>
<span>- knowing the values of the 3 terms as 3:8:15 gives a total of 3+8+15 = 26 ratio values </span>
<span>- you then simply divide the total weight by this ratio value total; 120/26 = 4.62 </span>
<span>- so each ratio value is 4.62 units of weight*** </span>
<span>- now, simply calculate the weight of each canid by multiplying its ratio value by the unit of weight... </span>
<span>fox; 3 x 4.62 = 13.86 </span>
<span>coyote; 8 x 4.62 = 36.96 </span>
<span>wolf; 15 x 4.62 = 69.3 </span>
<span>Validate the ratios by adding the weights together (we should get 120) 13.86 + 36.96 + 69.3 = 120.12 </span>
<span>The total is slightly out because that 4.62 figure was a rounding up. </span>
<span>Now, the thing is, there is nothing given that allows us to know exactly what ratio value the wolf should be, I chose 15 myself because that is a real-world plausible value when compared to 3:8 for the other 2. Changing it to 16, say, means that there are now 27 ratio values total giving a ratio value of 120/27 = 4.44 obviously changing the weights of all 3.</span>
